我正在玩HTTPServer，遇到了一个问题。我需要将ContentType标头添加到响应中，但当我这样做时，客户端会得到ERR_EMPTY_REPONSE。
如果我删除：
headers.add("Content-Type", "text/html");
然后服务器工作正常，但我需要为我的应用程序传递CType头。什么东西？如何包含内容类型标头？
/*
* EchoServer.java
*
* Accept an HTTP request and echo it back as the HTTP response.
*
* Copyright (c) 2005 Sun Microsystems, Inc
* Copyright (c) 2008 Operational Dynamics Consulting, Pty Ltd
*
* The code in this file is made available to you by its authors under the
* terms of the "GNU General Public Licence, version 2" See the LICENCE file
* for the terms governing usage and redistribution.
*/
/*
* This code is a simple derivation of the example in the package
* documentation for com.sun.net.httpserver, as found in file
* jdk/src/share/classes/com/sun/net/httpserver/package-info.java as shipped
* with the openjdk 1.6 b08 code drop. Used under the terms of the GPLv2.
*/
import static java.net.HttpURLConnection.HTTP_OK;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.net.InetSocketAddress;
import java.net.URLDecoder;
import java.util.List;
import com.sun.net.httpserver.Headers;
import com.sun.net.httpserver.HttpExchange;
import com.sun.net.httpserver.HttpExchange.*;
import com.sun.net.httpserver.HttpHandler;
import com.sun.net.httpserver.HttpServer;
/**
* Echo the body of an HTTP request back as the HTTP response. This is merely
* a simple exercise of the Secret Sun Web Server. As configured, the URL to
* access it is http://localhost:8000/echo.
*
* @author Andrew Cowie
*/
public final class Test {
public static void main(String[] args) throws IOException {
final InetSocketAddress addr;
final HttpServer server;
addr = new InetSocketAddress(8000);
server = HttpServer.create(addr, 10);
server.createContext("/echo", new EchoHandler());
server.start();
}
}
class EchoHandler implements HttpHandler {
public void handle(HttpExchange t) throws IOException {
final InputStream is;
final OutputStream os;
StringBuilder buf;
int b;
final String request, response;
buf = new StringBuilder();
/*
* Get the request body and decode it. Regardless of what you are
* actually doing, it is apparently considered correct form to consume
* all the bytes from the InputStream. If you don't, closing the
* OutputStream will cause that to occur
*/
is = t.getRequestBody();
while ((b = is.read()) != -1) {
buf.append((char) b);
}
is.close();
if (buf.length() > 0) {
request = URLDecoder.decode(buf.toString(), "UTF-8");
} else {
request = null;
}
/*
* Construct our response:
*/
buf = new StringBuilder();
buf.append("<html><head><title>HTTP echo server</title></head><body>");
buf.append("<p><pre>");
buf.append(t.getRequestMethod() + " " + t.getRequestURI() + " " + t.getProtocol() + "n");
/*
* Process the request headers. This is a bit involved due to the
* complexity arising from the fact that headers can be repeated.
*/
Headers headers = t.getRequestHeaders();
for (String name : headers.keySet()) {
List<String> values = headers.get(name);
for (String value : values) {
buf.append(name + ": " + value + "n");
}
}
/*
* If there was an actual body to the request, add it:
*/
if (request != null) {
buf.append("n");
buf.append(request);
}
buf.append("</pre></p>");
buf.append("</body></html>n");
response = buf.toString();
System.out.println(response);
/*
* And now send the response. We could have instead done this
* dynamically, using 0 as the response size (forcing chunked
* encoding) and writing the bytes of the response directly to the
* OutputStream, but building the String first allows us to know the
* exact length so we can send a response with a known size. Better :)
*/
headers.add("Content-Type", "text/html");
t.sendResponseHeaders(HTTP_OK, response.length());
os = t.getResponseBody();
os.write(response.getBytes());
/*
* And we're done!
*/
os.close();
t.close();
}
}
您正在从request中提取标头，更改请求标头没有任何意义。您将需要修改响应标头。您可以添加以下
t.getResponseHeaders().add("Content-Type", "text/html");