有可能实例化类的实例，作为参数传递给Scala中的泛型trait吗

Question

我有以下代码，用Scala 2.10.0编写：

trait A[T <: B] {
  self : { def foo() } =>
  val action : ()=>Unit = this.foo _
  //wanna make default for this
  val construction : String=>T
  def bar()(implicit x : String) : T = {
    action()
    val destination = construction(x)
    destination.baz()
    destination
  }
}
trait B { def baz() {} }
class Xlass { def foo() {} }
class Klass(a : String)(implicit val x : String) extends B {
    val f = new Xlass with A[Klass] {
        //boilerplate!
        val construction = new Klass(_)
    }
}
implicit val x = "Something"
val destination = new Klass("some a").f.bar()

我想知道，是否可以为construction设置默认值，例如val construction = new T(_)？目前我已经尝试了几个选项，但没有一个能满足此代码的所有特性，例如使用类型边界、隐式和结构类型。就我所能得到的而言，这是一个，但它在scala.ScalaReflectionException: free type T is not a class:中失败了

import reflect.runtime.universe._
val tT = weakTypeTag[T]
...
val privConstruction = 
  x : String => 
    runtimeMirror(tT.mirror.getClass.getClassLoader)
    //fails here with scala.ScalaReflectionException: free type T is not a class 
    .reflectClass(tT.tpe.typeSymbol.asClass) 
    .reflectConstructor(tT.tpe.members.head.asMethod)(x).asInstanceOf[T]

Answer 1

所以，最后，我做到了：

trait A[T <: B] {
  self : { def foo() } =>
  val action : ()=>Unit = this.foo _
  def construction(x: String)(implicit tag : reflect.ClassTag[T]) : T = {
    tag.runtimeClass.getConstructor(classOf[String], classOf[String]).newInstance(x, x).asInstanceOf[T]
  }
  def bar()(implicit x : String, tag : reflect.ClassTag[T]) : T = {
    action()
    val destination = construction(x)
    destination.baz()
    destination
  }
}
trait B { def baz() {} }
class Xlass { def foo() {} }
class Klass(a : String)(implicit val x : String) extends B {
    val f = new Xlass with A[Klass]
}
implicit val x = "Something"
val destination = new Klass("some a").f.bar()