PHP 中的计数数组给出意外的输出

Question

>我有以下 2 个数据：

$temp = Array
(
    [@url] => url
    [@type] => image/jpeg
    [@expression] => full
    [@width] => 644
    [@height] => 429
)
$count_total = count($temp); // gives me 5, how can it give me total = 1?

---

Array
(
    [0] => Array
        (
            [@url] => url1
            [@type] => image/jpeg
            [@expression] => full
            [@width] => 800
            [@height] => 621
        )
    [1] => Array
        (
            [@url] => url2
            [@type] => application/x-shockwave-flash
        )
)
this is total:2 // this is correct

如何将第一个数组计数为 1？

Answer 1

下面的

数组（由您给出）

$temp = Array
(
[@url] => url
[@type] => image/jpeg
[@expression] => full
[@width] => 644
[@height] => 429
)

有 5 个值，索引@url, @type, @expression, @width, @height .所以它总是会给你计数 5。

如果您想获得计数 1。你必须像下面这样做

$temp = Array(
    array(
        [@url] => url
        [@type] => image/jpeg
        [@expression] => full
        [@width] => 644
        [@height] => 429
    )
);

在这里count($temp)将为您提供输出 1

Answer 2

这将为您提供计数 1

$temp[] = Array
(
    [@url] => url
    [@type] => image/jpeg
    [@expression] => full
    [@width] => 644
    [@height] => 429
)
$count_total = count($temp);

Answer 3

     $temp = Array
     (
         [0] => Array
             (
            [@url] => url1
            [@type] => image/jpeg
            [@expression] => full
            [@width] => 800
            [@height] => 621
        )
)
 $count_total = count($temp);

如果您的数组在上面，则可以计数为 1;

Answer 4

如果得到单个结果，请执行以下操作：

$temp = Array
(
    [@url] => url
    [@type] => image/jpeg
    [@expression] => full
    [@width] => 644
    [@height] => 429
);

单一结果：

$new_temp[0] = $temp;

现在你得到：

count($new_temp); // get 1

Answer 5

$temp = Array 
       (
       [0] => Array
              (
                   [@url] => url
                   [@type] => image/jpeg
                   [@expression] => full
                   [@width] => 644
                   [@height] => 429
               )
       );
$count_total = count($temp); //gives you 1

问题是，在第一个代码块中，您正在尝试计算数组的元素数量，在第二个块中是另一个数组的 insido。

Answer 6

它正在计算数组中的元素数量。第一个是给你 5，因为数组有 5 个元素。第二个是给你 2，因为它是一个包含 2 个元素（数组）的多数组。

要使其返回一个，您可以将数组放在数组中，如下所示：

Array([0] => Array())

我希望这回答了你的问题。