select first(orderid), accountid
from [Order]
group by AccountId
order by DateCreated desc
first((是无效函数。
max((不适用于唯一标识符
如何获取为所有帐户创建的最后一个订单ID?谢谢
类似(未经测试(的东西:
;WITH CTE_LatestOrders AS (
select accountid, lastcreated = max(datecreated)
from [Order]
group by accountid
)
select
accountid, orderid
from
[Orders] o
join CTE_LatestOrders l
on o.AccountID = l.AccountID
and o.datecreated = l.lastcreated
Max((适用于自MS SQL 2012 起的唯一标识符
您也可以继续下面的操作。
Select Temp.orderid, T.AccountId, T.DateCreated
From
(
Select AccountId, max(DateCreated) as DateCreated
From [Order]
Group By AccountId
)T
Inner Join [Order] Temp on Temp.AccountId = T.AccountId
AND Temp.DateCreated = T.DateCreated
CTE不是UDT/temp表;将CTE视为仅为当前查询定义的视图。就像视图一样,CTE被展开并折叠到整个查询计划中。全局优化仍然会发生,但不要因为使用了CTE就只执行一次查询。这里有一个适合这个空间的琐碎例子:WITH vw AS(SELECT COUNT(*(c FROM Person(SELECT a.c,b.c FROM vw a,vw b;查询计划将清楚地显示两次扫描/聚合和一个联接,而不是仅仅投影两次相同的结果。