如何获得唯一的联系号码，从我的联系人应用程序在android

Question

我正在制作联系应用程序，但是当我获得所有联系号码时，我得到了重复的号码。我如何确保我只得到唯一的号码?

ContentResolver cr = getContentResolver();
        Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null);
        if (cur != null && cur.getCount() > 0) {
            while (cur.moveToNext()) {
                strPhontNumberTemp = "";
                mPhoneContactsVo = new PhoneContactsVo();
                String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
                String name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
                if (Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
                    Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,  ContactsContract.CommonDataKinds.Phone.CONTACT_ID
                            + " = ?", new String[] { id }, null);
                     while (pCur.moveToNext()) {
                         String phoneNumber = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                         Log.i(TAG, "phoneNumber="+phoneNumber); // Dupblicate number print
                     }
                }
            }
        }

Answer 1

使用Set Interface添加电话号码，避免重复。

Set<String> uniques = new HashSet<String>();

检查这个简单的例子

   public static void main(String[] args) {
    Set<String> uniques = new HashSet<String>();
    Set<String> dups    = new HashSet<String>();
    for (String a : args)
        if (!uniques.add(a))
            dups.add(a);
    // Destructive set-difference
    uniques.removeAll(dups);
    System.out.println("Unique words:    " + uniques);
    System.out.println("Duplicate words: " + dups);
  }

从这个链接…http://docs.oracle.com/javase/tutorial/collections/interfaces/set.html