我对rails非常陌生,并尝试使一个先进的搜索表单,它需要两个值'blood_group'和'area',并基于该搜索从数据库中获取记录,并将显示在同一页面上(find.html.erb)我在find.html.erb中尝试了一些东西,但是出现了一个错误"未定义的方法[]for nil: nil类",其中我的搜索表单存在。请帮忙解决这个错误。
这是我在find.html.erb中的搜索表单
<%= form_tag find_path , method: :get do %>
<p> <%= label_tag :blood_group %><br />
<%= select_tag (:blood_group), options_for_select(%w[ A+ B+ O+ AB+ A- B- O- AB-]), params[:blood_group] %> </p>
<p> <%= label_tag :area %><br />
<%= select_tag (:area), options_for_select(%w[Indore Vijay_Nagar Bhawar_Kuwa Rajendra_Nagar Geeta_Bhawan Aerodram Tejaji_Nagar Raj_Mohalla Rajwada Chandan_Nagar Gandhi_Nagar Arvindo MY Bombay_Hospital]) , params[:area] %> </p>
<%= submit_tag "Search" , class: "btn btn-primary" , name: nil %>
<% end %>
错误出现在我使用select标记的行。下面是我在捐赠者控制器
中的查找操作def find
@donors = Donor.search(params[:blood_group], params[:area]).all
end
和捐助。Rb如下
class Donor < ActiveRecord::Base
def self.search(blood_group, area)
return all unless blood_group.present? || area.present?
where(['blood_group LIKE ? AND area LIKE ?', "%#{blood_group}%", "%#{area}%"])
end
结束您的搜索表单必须是这样的:
<%= form_tag find_path , method: :get, remote: true do %>
<p> <%= label_tag :blood_group %><br />
<%= select_tag (:blood_group), options_for_select(%w[ A+ B+ O+ AB+ A- B- O- AB-]) %> </p>
<p> <%= label_tag :area %><br />
<%= select_tag (:area), options_for_select(%w[Indore Vijay_Nagar Bhawar_Kuwa Rajendra_Nagar Geeta_Bhawan Aerodram Tejaji_Nagar Raj_Mohalla Rajwada Chandan_Nagar Gandhi_Nagar Arvindo MY Bombay_Hospital]) %> </p>
<%= submit_tag "Search" , class: "btn btn-primary" , name: nil %>
<% end %>
将控制器修改为:
def find
@donors = Donor.search(params[:blood_group], params[:area]).all
respond_to do |format|
format.js
end
end
然后添加find.js.erb显示搜索的内容