所以我试图在运行Raspbian的RaspberryPi上从Makefile运行sed命令。当我直接在终端中键入命令时,我使用的命令非常有效,但当我试图从Makefile中执行它们时,我得到了以下反馈:
sed:-e表达式#1,字符14:命令后的额外字符
#
# Quick and dirty Makefile for logsnag
#
CC = gcc
INCLUDE = -I.
CFILES = myThing.c
OBJS = myThing.o
CFLAGS = ${INCLUDE}
all: myThing
myThing: ${OBJS}
${CC} ${CFLAGS} ${OBJS} -o myThing
myThing.o: ${CFILES}
${CC} ${CFLAGS} myThing.c -c
install: myThing
sudo cp -f myThing/usr/local/bin
sudo cp -f ../bin/startlogging.sh /usr/local/bin
sudo cp -f ../cfg/rotateThing.cfg /etc
if [ ! -d /var/log/thingLog ]; then
sudo mkdir /var/log/thingLog;
fi;
sudo sed -i -e '$i touch /var/log/thingLog/thing.log /var/log/thingLog/myThing n' /etc/rc.local;
sudo sed -i -e '$i logrotate -f /etc/rotateThing.cfg n' /etc/rc.local;
sudo sed -i -e '$i touch /var/log/thingLog/thing.log /var/log/thingLog/myThing n' /etc/rc.local;
sudo sed -i -e '$i /usr/local/bin/startlogging.sh > /var/log/thingLog/myThing 2>&1 & n' /etc/rc.local;
clean:
rm -f myThing *.o
您的问题是Makefile变量扩展看起来很像shell变量扩展。也就是说,如果Makefile中有一个单字母变量:
X=Some string
然后你引用这个变量,比如:
$X
因此,当您在一个构建节中有这样的命令时:
sed -i -e '$i /usr/local/bin/startlogging.sh > /var/log/thingLog/myThing 2>&1 & n'
$i
被make(使用空字符串)替换为,导致无效的CCD_ 2命令。您可以通过以下方式转义$
来解决此问题:加倍:
sed -i -e '$$i /usr/local/bin/startlogging.sh > /var/log/thingLog/myThing 2>&1 & n'
Make中对此进行了讨论文档