我想下载一个文件,该文件在打开带有链接的页面时下载https://data.gov.in/resources/all-india-pincode-directory/download在ruby 中
我希望这能对你有所帮助,
puts " download start"
url = 'https://data.gov.in/resources/all-india-pincode-directory/download '
open('all_india_pin_code.csv', 'wb') do |file|
file << open(url).read
end
puts " download end"
有一个名为Open URI的标准库。。。你试过了吗?
require 'open-uri'
file = open("https://data.gov.in/resources/all-india-pincode-directory/download")