序列化名为 "return" 的 JSON 对象

Question

>我正在尝试针对Mt Gox的Http API编写一个代码。它返回如下所示的 JSON：

{
"result":"success",
"return":
 {
 "high": {"value":"5.70653","value_int":"570653","display":"$5.70653","currency":"USD"},
 "low": {"value":"5.4145","value_int":"541450","display":"$5.41450","currency":"USD"},
 "avg": {"value":"5.561119626","value_int":"556112","display":"$5.56112","currency":"USD"},
 "vwap": {"value":"5.610480461","value_int":"561048","display":"$5.61048","currency":"USD"},
 "vol": {"value":"55829.58960346","value_int":"5582958960346","display":"55,829.58960346u00a0BTC","currency":"BTC"},
 "last_all":{"value":"5.5594","value_int":"555940","display":"$5.55940","currency":"USD"},
 "last_local":{"value":"5.5594","value_int":"555940","display":"$5.55940","currency":"USD"},
 "last_orig":{"value":"5.5594","value_int":"555940","display":"$5.55940","currency":"USD"},
 "last":{"value":"5.5594","value_int":"555940","display":"$5.55940","currency":"USD"},
 "buy":{"value":"5.53587","value_int":"553587","display":"$5.53587","currency":"USD"},
 "sell":{"value":"5.56031","value_int":"556031","display":"$5.56031","currency":"USD"}
 }
}

我正在尝试将该信息转换为对象。我制作了一组看起来像这样的类：

[DataContract]
class MtGoxResponse
{
    public string result { get; set; }
    [DataMember(Name="return")]
    public Resp Resp { get; set; }
}
[DataContract]
class Resp
{
    public HLA high { get; set; }
    public HLA low { get; set; }
    public HLA avg { get; set; }
    public HLA vwap { get; set; }
    public HLA vol { get; set; }
    public HLA last_all { get; set; }
    public HLA last_local { get; set; }
    public HLA last_orig { get; set; }
    public HLA last { get; set; }
    public HLA buy { get; set; }
    public HLA sell { get; set; }
}
[DataContract]
class HLA
{
    public double value { get; set; }
    public int value_int { get; set; }
    public string display { get; set; }
    public string currency { get; set; }
}

Result每次都很好，但Resp总是空的。我是否缺少具有DataContract属性的内容？我假设根本原因是对象的名称，但肯定有办法解决它。

Answer 1

我不确定为什么您的[DataMember]属性不起作用。从我所读到的内容来看，[DataMember]似乎对序列化程序的每个实现有不同的解释，因此它很可能是一个错误。

但是，您可以通过简单地在return之前使用 @ 符号来消除使用它的需要，如下所示：

[DataContract]
class MtGoxResponse
{
    public string result { get; set; }
    public Resp @return { get; set; }
}

此前缀在 MSDN 的 C# 关键字页面上被被动提及。