解决多个提升查询

Question

Solr 3.6.2中提升静态值的最佳方法是什么？

每个文档都有一个(KeywordTokenized(source值(信息来源(，我想表达一些值比其他值更重要。如果有帮助，完全内容控制是可能的。

http://localhost:8080/solr/index/select?fl=source,score
  &defType=edismax
  &qf=title^4
  &q=qux
  &bq=source:foo^10
  &bq=source:bar^14

不幸的是，加法boost查询实际上没有效果。解析后的查询如下所示(qux源于qu(

+DisjunctionMaxQuery(((title:qux qu)^4.0))) source:foo^10.0 source:bar^14.0

调试查询前两个不显著尊重bq=source:foo^10 的结果

5.366351 = (MATCH) sum of: 5.366351 = (MATCH) sum of: 2.067319 = (MATCH) weight(title:qux in 4472), product of: 0.5513683 = queryWeight(title:qux), product of: 7.4988675 = idf(docFreq=35, maxDocs=23918) 0.073526874 = queryNorm 3.7494338 = (MATCH) fieldWeight(title:qux in 4472), product of: 1.0 = tf(termFreq(title:qux)=1) 7.4988675 = idf(docFreq=35, maxDocs=23918) 0.5 = fieldNorm(field=title, doc=4472) 3.299032 = (MATCH) weight(title:qu in 4472), product of: 0.69651634 = queryWeight(title:qu), product of: 9.472949 = idf(docFreq=4, maxDocs=23918) 0.073526874 = queryNorm 4.7364745 = (MATCH) fieldWeight(title:qu in 4472), product of: 1.0 = tf(termFreq(title:qu)=1) 9.472949 = idf(docFreq=4, maxDocs=23918) 0.5 = fieldNorm(field=title, doc=4472)
5.281746 = (MATCH) sum of: 4.134638 = (MATCH) sum of: 4.134638 = (MATCH) weight(title:qux in 4402), product of: 0.5513683 = queryWeight(title:qux), product of: 7.4988675 = idf(docFreq=35, maxDocs=23918) 0.073526874 = queryNorm 7.4988675 = (MATCH) fieldWeight(title:qux in 4402), product of: 1.0 = tf(termFreq(title:qux)=1) 7.4988675 = idf(docFreq=35, maxDocs=23918) 1.0 = fieldNorm(field=title, doc=4402) 1.147108 = (MATCH) weight(source:foo^10.0 in 4402), product of: 0.45919293 = queryWeight(source:foo^10.0), product of: 10.0 = boost 2.4980958 = idf(docFreq=5346, maxDocs=23918) 0.018381719 = queryNorm 2.4980958 = (MATCH) fieldWeight(source:foo in 4402), product of: 1.0 = tf(termFreq(source:foo)=1) 2.4980958 = idf(docFreq=5346, maxDocs=23918) 1.0 = fieldNorm(field=source, doc=4402)

值得注意的是，第一个结果对于source具有noqueryWeight，尽管在source字段中具有值。fieldNorm也有点不同，这是由于

Answer 1

问题很可能是由queryNorm引起的。请参阅：http://lucene.472066.n3.nabble.com/QueryNorm-and-FieldNorm-td1992964.html

只要你不是根据不同查询的分数来比较结果，那么在单个搜索中的相关性排序应该是可以的。