我正在尝试使用PHP上传视频到Youtube。我正在使用Youtube API v3，我正在使用最新的Google API PHP客户端库的源代码。
我正在使用
上给出的示例代码https://code.google.com/p/google-api-php-client/进行鉴权。身份验证通过很好，但当我尝试上传视频时，我得到错误代码500和消息为空的Google_ServiceException。
我看了一下之前问的问题:使用php client library v3上传视频到youtube，但是公认的答案并没有描述如何指定要上传的文件数据。我发现另一个类似的问题与Youtube API v3和PHP上传文件，在评论中提到categoryId是强制性的，因此我尝试在代码片段中设置categoryId，但它仍然给出相同的异常。
我还参考了文档站点(https://developers.google.com/youtube/v3/docs/videos/insert)上的Python代码，但我无法在客户端库中找到next_chunk函数。但是我尝试放置一个循环(在代码片段中提到)来重试获得错误代码500，但在所有10次迭代中，我得到相同的错误。
下面是我正在尝试的代码片段:
$youTubeService = new Google_YoutubeService($client);
if ($client->getAccessToken()) {
print "Successfully authenticated";
$snippet = new Google_VideoSnippet();
$snippet->setTitle = "My Demo title";
$snippet->setDescription = "My Demo descrition";
$snippet->setTags = array("tag1","tag2");
$snippet->setCategoryId(23); // this was added later after refering to another question on stackoverflow
$status = new Google_VideoStatus();
$status->privacyStatus = "private";
$video = new Google_Video();
$video->setSnippet($snippet);
$video->setStatus($status);
$data = file_get_contents("video.mp4"); // This file is present in the same directory as the code
$mediaUpload = new Google_MediaFileUpload("video/mp4",$data);
$error = true;
$i = 0;
// I added this loop because on the sample python code on the documentation page
// mentions we should retry if we get error codes 500,502,503,504
$retryErrorCodes = array(500, 502, 503, 504);
while($i < 10 && $error) {
try{
$ret = $youTubeService->videos->insert("status,snippet",
$video,
array("data" => $data));
// tried the following as well, but even this returns error code 500,
// $ret = $youTubeService->videos->insert("status,snippet",
// $video,
// array("mediaUpload" => $mediaUpload);
$error = false;
} catch(Google_ServiceException $e) {
print "Caught Google service Exception ".$e->getCode()
. " message is ".$e->getMessage();
if(!in_array($e->getCode(), $retryErrorCodes)){
break;
}
$i++;
}
}
print "Return value is ".print_r($ret,true);
// We're not done yet. Remember to update the cached access token.
// Remember to replace $_SESSION with a real database or memcached.
$_SESSION['token'] = $client->getAccessToken();
} else {
$authUrl = $client->createAuthUrl();
print "<a href='$authUrl'>Connect Me!</a>";
}
是我做错了什么吗?
我能够使用以下代码获得上传工作:
if($client->getAccessToken()) {
$snippet = new Google_VideoSnippet();
$snippet->setTitle("Test title");
$snippet->setDescription("Test descrition");
$snippet->setTags(array("tag1","tag2"));
$snippet->setCategoryId("22");
$status = new Google_VideoStatus();
$status->privacyStatus = "private";
$video = new Google_Video();
$video->setSnippet($snippet);
$video->setStatus($status);
$error = true;
$i = 0;
try {
$obj = $youTubeService->videos->insert("status,snippet", $video,
array("data"=>file_get_contents("video.mp4"),
"mimeType" => "video/mp4"));
} catch(Google_ServiceException $e) {
print "Caught Google service Exception ".$e->getCode(). " message is ".$e->getMessage(). " <br>";
print "Stack trace is ".$e->getTraceAsString();
}
}
我知道这是旧的，但这里是文档中的答案:
// REPLACE this value with the path to the file you are uploading.
$videoPath = "/path/to/file.mp4";
$snippet = new Google_Service_YouTube_VideoSnippet();
$snippet->setTitle("Test title");
$snippet->setDescription("Test description");
$snippet->setTags(array("tag1", "tag2"));
// Numeric video category. See
// https://developers.google.com/youtube/v3/docs/videoCategories/list
$snippet->setCategoryId("22");
// Set the video's status to "public". Valid statuses are "public",
// "private" and "unlisted".
$status = new Google_Service_YouTube_VideoStatus();
$status->privacyStatus = "public";
// Associate the snippet and status objects with a new video resource.
$video = new Google_Service_YouTube_Video();
$video->setSnippet($snippet);
$video->setStatus($status);
// Specify the size of each chunk of data, in bytes. Set a higher value for
// reliable connection as fewer chunks lead to faster uploads. Set a lower
// value for better recovery on less reliable connections.
$chunkSizeBytes = 1 * 1024 * 1024;
// Setting the defer flag to true tells the client to return a request which can be called
// with ->execute(); instead of making the API call immediately.
$client->setDefer(true);
// Create a request for the API's videos.insert method to create and upload the video.
$insertRequest = $youtube->videos->insert("status,snippet", $video);
// Create a MediaFileUpload object for resumable uploads.
$media = new Google_Http_MediaFileUpload(
$client,
$insertRequest,
'video/*',
null,
true,
$chunkSizeBytes
);
$media->setFileSize(filesize($videoPath));
// Read the media file and upload it chunk by chunk.
$status = false;
$handle = fopen($videoPath, "rb");
while (!$status && !feof($handle)) {
$chunk = fread($handle, $chunkSizeBytes);
$status = $media->nextChunk($chunk);
}
fclose($handle);
// If you want to make other calls after the file upload, set setDefer back to false
$client->setDefer(false);
我也意识到这是旧的，但是当我从GitHub克隆了最新版本的php-client时，我遇到了Google_Service_YouTube_Videos_Resource::insert()方法的麻烦。
我会传递一个数组与"data" => file_get_contents($pathToVideo)和"mimeType" => "video/mp4"集作为insert()方法的参数，但我仍然不断得到(400) BadRequest作为回报。
调试和阅读谷歌的代码，我发现在GoogleServiceResource.php中有一个检查(在第179-180行)针对一个数组键"uploadType"，将启动Google_Http_MediaFielUpload对象。
$part = 'status,snippet';
$optParams = array(
"data" => file_get_contents($filename),
"uploadType" => "media", // This was needed in my case
"mimeType" => "video/mp4",
);
$response = $youtube->videos->insert($part, $video, $optParams);
如果我没记错的话，在PHP-api的0.6版本中，不需要uploadType参数。这可能只适用于direct上传样式，而不适用于Any Day's answer中显示的resumable上传样式。
答案是通过Google PHP客户端库使用Google_Http_MediaFileUpload。
下面是示例代码:https://github.com/youtube/api-samples/blob/master/php/resumable_upload.php