检测符号后面的字符

Question

我正在尝试以两种方式编写一个方法 - 如果符号 $ 后面的字符是整数，那么我想转到第二个 if 语句并执行它。如果符号 $ 后面的字符是数字（或字母），那么我想将该数字设置为 16，并且每次使用新数字时，我都想将 setNumber 增加 1。这是我尝试过的：

for (i=0; i<anyLines.length; i++) {
            int setNumber = 16;
            // 1st IF statement
            if (Character.isDigit(anyLines[i].charAt(the character after $)))
                        anyLines[i] = anyLines[i].replace("$","");
                        anyLines[i] = anyLines[i].replace(charAt(after zero),setNumber);
                        // Increment set number if a new digit is detected
                    }
            else {
                        continue;
                 }
            // 2nd IF statement
            if (anyLines[i].isInteger(anyLines[i].charAt(the character after $))) {
                anyLines[i] = anyLines[i].replace("$","");
                anyLines[i] = Integer.toBinaryString(131072  
+(Integer.parseInt(anyLines[i]))).substring(1,17);
            }
            else {
                continue;
            }

我不知道该怎么做。

Answer 1

像这样：

public static void main(String[] args) {
    String s = "af$Aklj$4r8$7jlkf$;a4$";
    char[] cs = s.toCharArray();
    for (int i = 0; i < cs.length; i++) {
        if (cs[i] == '$') {
            if (i + 1 < cs.length) {
                i++;
                if (Character.isDigit(cs[i])) {
                    System.out.print("digit after $: ");
                } else if (Character.isLetter(cs[i])) {
                    System.out.print("letter after $: ");
                } else {
                    System.out.print("unhandled character after $: ");
                }
                System.out.println(String.copyValueOf(cs, i-1, 2));
            }
        }
    }
}