从file_get_contents请求获取IP

Question

我有两个页面，其中一个发送file_get_contents请求:

$postdata = http_build_query( array('install' => 'true', 'url' => $_SERVER['SERVER_NAME'], 'key' => 'XXXXXXXXXXXX') );
$opts = array('http' =>
    array(
        'method'  => 'POST',
        'header'  => 'Content-type: application/x-www-form-urlencoded',
        'content' => $postdata
    )
);
$context  = stream_context_create($opts);
$registration_key = file_get_contents('http://example.com/register.php', false, $context);

和一个接收呼叫的页面(http://example.com/register.php)，我试图抓取请求来自何处的IP，但无济于事。我试过了:

$_SERVER['HTTP_CLIENT_IP']

$_SERVER['HTTP_VIA']

$_SERVER['HTTP_X_FORWARDED_FOR']

$_SERVER['REMOTE_ADDR'] (IP，但不是发送或接收请求的计算机的IP)

我在哪里可以找到发送请求的计算机上的更多信息?

提前感谢!

Answer 1

仅当您在请求中传递IP时:

$registration_key = file_get_contents('http://example.com/register.php?ip='.$_SERVER['REMOTE_ADDR'], false, $context);