我有一个这样的表结构
id | itemId | date |
1 | a1 | 6/14/2015
2 | a1 | 3/14/2015
3 | a1 | 2/14/2015
4 | b1 | 6/14/2015
5 | c1 | 6/14/2015
从这个表结构中,我试图获取所有具有最小日期的不同项目。 例如,我正在尝试获取id = 3,4和5。
我尝试过遵循代码,但我不能
var items = (from i in _db.Items
//where min(i.date) // doesn't seem right
group i by i.itemID
into d select new
{
iId = d.Key,
}).Distinct();
鉴于您的示例数据,我会这样做:
var query =
from i in _db.Items
group i by i.itemId into gis
let lookup = gis.ToLookup(x => x.date, x => x.id)
from x in lookup[gis.Min(y => y.date)]
select x;
var items = from i in _db.Items
group i.date by i.itemID
into d select new {
iId = d.Key, iDate = d.Min()
};