所以我写了这段代码,它可以解析start
对象的属性路径,返回所需的属性,并为source
对象取一个out参数,返回的属性可以对其调用:
public static PropertyInfo GetProperty(string path, object start, out object source)
{
if (string.IsNullOrEmpty(path))
throw new ArgumentException();
source = start;
var pType = source.GetType();
var paths = path.Split('.');
PropertyInfo pInfo = null;
for (int i = 0; i < paths.Length; i++) {
var subpath = paths[i];
pInfo = pType.GetProperty(subpath);
if (i < paths.Length - 1) { // wonder if there's a better way writing this to avoid this if?
source = pInfo.GetValue(source);
pType = source.GetType();
}
}
return pInfo;
}
现在假设我有以下层次结构:
public class Object
{
public string Name { get; set; }
}
public class GameObject : Object { }
public class Component : Object
{
public GameObject gameObject { get; set; }
}
public class MonoBehaviour : Component { }
public class Player : MonoBehaviour { }
public class GameManager : MonoBehaviour
{
public Player player { get; set; }
}
示例用法:
var game = new GameManager
{
player = new Player { gameObject = new GameObject { Name = "Stu"} }
};
// somewhere else...
object source;
var name = GetProperty("player.gameObject.Name", game, out source);
var value = name.GetValue(source); // returns "Stu"
我的问题是:这显然只适用于属性,我如何使它同时适用于属性和字段?-问题是,MemberInfo
在FieldInfo
和PropertyInfo
之间很常见,但它没有GetValue
,所以我不能返回MemberInfo
。我一直在读关于表情的文章,但不确定它们在这里对我有什么帮助。。。
同样,我想要的是(给定一个源)解析以下内容的能力:X.Y.Z
,其中X、Y、Z可以是属性或字段。
编辑:
所以我修改了一些代码来做我想做的事情——但这不是你所说的干净的代码,太多的参数:
public static bool TryParse(string path, object start, out PropertyInfo pinfo, out FieldInfo finfo, out object source)
{
if (string.IsNullOrEmpty(path))
throw new ArgumentException();
var type = start.GetType();
var paths = path.Split('.');
source = start;
pinfo = null;
finfo = null;
for (int i = 0; i < paths.Length; i++) {
var subpath = paths[i];
pinfo = type.GetProperty(subpath);
if (pinfo == null) {
finfo = type.GetField(subpath);
if (finfo == null)
return false;
}
if (i < paths.Length - 1) {
source = pinfo == null ? finfo.GetValue(source) : pinfo.GetValue(source);
type = source.GetType();
}
}
return true;
}
用法:
var game = new GameManager
{
player = new Player { gameObject = new GameObject { Name = "Stu" } }
};
object source;
PropertyInfo pinfo;
FieldInfo finfo;
if (TryParse("player.gameObject.Name", game, out pinfo, out finfo, out source)) {
var value = pinfo == null ? finfo.GetValue(source) : pinfo.GetValue(source);
}
它完成了我想要的解析,但一定有更好的。。。
我认为您可以尝试使用我的免费开源库Dynamic Expresso。
你可以写这样的东西:
var game = new GameManager
{
player = new Player { gameObject = new GameObject { Name = "Stu" } }
};
var interpreter = new Interpreter();
var parameters = new[] {
new Parameter("game", game)
};
var result = interpreter.Eval("game.player.gameObject.Name", parameters);
您还可以提取解析后的Expression
以获取有关属性/字段的信息,它还支持更复杂的操作(索引器、函数…)。解析后的表达式会被编译,可以调用一次或多次。
这里很热,它可以在表达式树上(不检查null和属性是否存在):
using System;
using System.Collections.Generic;
using System.Linq;
using System.Linq.Expressions;
namespace ExpressionTrees
{
public static class ExpressionTreeBuilder
{
private static readonly IDictionary<string, Delegate> Lambdas =
new Dictionary<string, Delegate>();
public static T GetValue<T, TInst>(this TInst obj, string propPath, T defVal = default(T))
{
var key = String.Format("{0};{1}", propPath, "str");//typeof(T).Name);
Delegate del;
if (!Lambdas.TryGetValue(key, out del))
{
var instance = Expression.Parameter(typeof(TInst), "obj");
var currentExpression =
propPath
.Split('.')
.Aggregate((Expression)instance, Expression.PropertyOrField);
var lexpr = Expression.Lambda<Func<TInst, T>>(currentExpression, instance);
del = lexpr.Compile();
Lambdas.Add(key, del);
}
var action = (Func<TInst, T>)del;
return action.Invoke(obj);
}
}
}
使用示例:
var surv = new Survey() { id = 1, title = "adsf" , User = new User() { Name = "UserName 11"}};
var dynamicUserName = surv.GetValue<string, Survey>("User.Name");
当然,最好使用经过良好测试和文档记录的第三方库。这个代码片段只是一个例子。