在Ruby中比较时间的正确方法是什么?

Question

下面的例子让我很困惑。为什么比较返回false?

require 'active_support/time'
time1 = Time.new.utc.end_of_day  # 2013-01-09 23:59:59 UTC
time2 = Time.parse(time1.to_s)   # 2013-01-09 23:59:59 UTC
time1 == time2                   # false
time1.eql?(time2)                # false 
time1.equal?(time2)              # false

我做错了什么?

Answer 1

time2是由缺乏信息的time1的字符串表示生成的。即微秒。

require 'active_support/time'
time1 = Time.new.utc.end_of_day  # => 2013-01-09 23:59:59 UTC
time2 = Time.parse(time1.to_s)   # => 2013-01-09 23:59:59 UTC
time1.usec # => 999999
time2.usec # => 0

处理:

如果不需要微秒精度，可以将两个时间戳四舍五入到秒。

time1.to_i == time2.to_i # => true