我正在做Spring Boot项目并使用Spring - Boot -jpa (Hibernate实现)。我在配置实体之间的下列关系时遇到麻烦。
让我们假设我需要两个表之间的多对一(和反向一对多)关系(MySQL在这个例子中,table1
逻辑上存储在各种其他表中的代码描述):
CREATE TABLE `table1` (
`id` INT NOT NULL AUTO_INCREMENT,
`ref_table` VARCHAR(50) NOT NULL,
`ref_column` VARCHAR(50) NOT NULL,
`code` VARCHAR(10) NOT NULL,
`description` VARCHAR(100) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE INDEX `u_composite1` (`ref_table` ASC, `ref_column` ASC, `code` ASC));
CREATE TABLE `table2` (
`id` INT NOT NULL AUTO_INCREMENT,
`field1` VARCHAR(100) NULL,
`code` VARCHAR(10) NOT NULL,
PRIMARY KEY (`id`));
我在SQL中连接这两个表的方法是这样的:
SELECT t2.*, t1.description
FROM table2 t2
JOIN table1 t1
ON ( t1.ref_table = 'table2'
AND t1.ref_column = 'code'
AND t1.code = t2.code);
所以,我创建了这样的实体(减去getter和setter):
@Entity
@Table(name = "table1")
public class Table1 implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(unique = true, nullable = false)
private int id;
@Column(nullable = false, length = 10)
private String code;
@Column(length = 100)
private String description;
@Column(name = "ref_column", nullable = false, length = 50)
private String refColumn;
@Column(name = "ref_table", nullable = false, length = 50)
private String refTable;
@OneToMany(mappedBy = "table1")
private List<Table2> table2;
}
@Entity
@Table(name = "table2")
public class Table2 implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(unique = true, nullable = false)
private int id;
@Column(nullable = false, length = 45)
private String field1;
@ManyToOne(fetch=FetchType.LAZY)
@Column(name = "code")
@JoinColumns({
@JoinColumn(name = "code", referencedColumnName = "code", nullable = false, updatable = false),
@JoinColumn(name = "'table2'", referencedColumnName = "ref_table", nullable = false, updatable = false),
@JoinColumn(name = "'code'", referencedColumnName = "ref_column", nullable = false, updatable = false)
})
private Table1 table1;
}
但是它不起作用。(
这种关系可以在JPA中定义吗?如果有,请告诉我怎么做?
关于"连接常量值"的问题,我设法使它工作使用@Where Hibernate注释:
-
如何用硬编码值替换@JoinColumn ?
@Entity @Table(name = "a") public class A { @Id @GeneratedValue(strategy = GenerationType.AUTO) public long id; @OneToMany @JoinColumn(name = "id", referencedColumnName = "id") @Where(clause = "blah = 'CONSTANT_VALUE'") public Set<B> b; protected A() {} } @Entity @Table(name = "b") public class B { @Id @Column(nullable = false) public Long id; @Column(nullable = false) public String blah; protected B() {} }