从微调器中删除最后一项将删除整个列表

Question

我正在尝试使用使用户能够删除任何列表元素的微调器控件。我有一个"添加"按钮将元素添加到列表中，还有一个"删除"按钮，可以从列表中删除当前显示的项目。

它按预期工作，除非用户删除列表中的最后一项。此时，将删除列表的所有项目。

我的代码如下：

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
    // grab our UI elements so we can manipulate them (for the Spinner)
    // or add listeners to them (in the case of the buttons)
    m_myDynamicSpinner = (Spinner)findViewById(R.id.dynamicSpinner);
    m_addItemText = (EditText)findViewById(R.id.newSpinnerItemText);
    Button addButton = (Button)findViewById(R.id.AddBtn);
    Button clearButton = (Button)findViewById(R.id.ClearBtn);
    // create an arrayAdapter an assign it to the spinner
    m_adapterForSpinner = new ArrayAdapter(this, android.R.layout.simple_spinner_item);
        ((ArrayAdapter)m_adapterForSpinner).setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    m_myDynamicSpinner.setAdapter(m_adapterForSpinner);
    // add listener for addButton
    addButton.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {
            addNewSpinnerItem();
        }
    });
    clearButton.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {
            clearSpinnerItems();
        }
    });
}
// add listener for addButton
private void addNewSpinnerItem() {
    if (m_addItemText.getText().length() == 0) {
        Toast.makeText(getApplicationContext(), "The textView is empty", Toast.LENGTH_LONG).show();
    } else {
        CharSequence textHolder = "" + m_addItemText.getText();
        ((ArrayAdapter) m_adapterForSpinner).add(textHolder);
    }
    m_addItemText.setText("");
}
private void clearSpinnerItems() {
    m_myDynamicSpinner.setOnItemSelectedListener(new OnItemSelectedListener() {
        @Override
        public void onItemSelected(AdapterView<?> parent, View view, int pos, long id) {
            Object t = m_adapterForSpinner.getItem(pos);
            ((ArrayAdapter) m_adapterForSpinner).remove((CharSequence) t);
        }
        @Override
        public void onNothingSelected(AdapterView<?> arg0) {
            // TODO
        }
    });
}

有没有人对如何完成这项工作有任何想法或建议？

Answer 1

代码的问题在于删除是在 onItemSelected 回调中，每次删除条目时都会调用该回调，从而递归删除，直到您实际上没有更多条目可供选择。如果在该方法中添加日志：

Log.d("Spinner", "Count: " + m_adapterForSpinner.getCount());

你会明白我的意思。我相信你可以想出更优雅的代码，但一个快速而肮脏的技巧是设置一个布尔标志来在第一次删除后停止递归。请参阅下面的代码片段，并将注释的行添加到您自己的代码中：

public class SpinnerTest extends Activity {
    Spinner m_myDynamicSpinner;
    EditText m_addItemText;
    ArrayAdapter m_adapterForSpinner;
    public static boolean cleared = false;  //   <--- set up a static boolean here
       @Override
        public void onCreate(Bundle savedInstanceState) {
// all your code unchanged
        clearButton.setOnClickListener(new OnClickListener() {
            public void onClick(View v) {
                cleared=false;   //   <--- nope, we did not clear the value yet
                clearSpinnerItems();
            }
        });
    }
// code unchanged
    private void clearSpinnerItems() {
        m_myDynamicSpinner.setOnItemSelectedListener(new OnItemSelectedListener() {
            public void onItemSelected(AdapterView<?> parent, View view, int pos, long id) {
                Object t = m_adapterForSpinner.getItem(pos);
                Log.d("Spinner", "Count: " + m_adapterForSpinner.getCount());
                if (!cleared)  //   <--- did I do it already?
                    ((ArrayAdapter) m_adapterForSpinner).remove((CharSequence) t);
                Log.d("Spinner", "Count: " + m_adapterForSpinner.getCount());
                cleared=true;  // I did it!
            }
// code unchanged

Answer 2

我无法理解您的问题。无论如何，您可以使用getSelectedItemPosition（）方法获取所选项目的位置。