Python输入超时

Question

是否有可能超时python 3输入?我成功地在Java中做了我想做的事情，但是你怎么能在python中做到呢?您可以使用jython并设法编译它，以便它不需要安装jython就可以运行(我只在目标计算机上有可用的python)吗?

import java.io.IOException;
public class TimedRead {
    public static String timedRead(int timeout) {
        long startTime = System.currentTimeMillis();
        long endTime = 0;
        char last = '0';
        String data = "";
        while(last != 'n' && (endTime = System.currentTimeMillis()) - startTime < timeout) {
            try {
                if(System.in.available() > 0) {
                    last = (char) System.in.read();
                    data += last;
                }
            } catch (IOException e) {
                e.printStackTrace();
                return "IO ERROR";
            }
        }
        if(endTime - startTime >= timeout) {
            return null;
        } else {
            return data;
        }
    }
    public static void main(String[] args) {
        String data = timedRead(3000);
        System.out.println(data);
    }
}

谢谢。编辑:

我可以抛出一个错误导致线程停止。

import signal
#This is an "Error" thrown when it times out
class Timeout(IOError):
    pass
def readLine(timeout):
    def handler(signum, frame):
        #Cause an error
        raise Timeout()
    try:
        #Set the alarm
        signal.signal(signal.SIGALRM, handler)
        signal.alarm(timeout)
        #Wait for input
        line = input()
        #If typed before timed out, disable alarm
        signal.alarm(0)
    except Timeout:
        line = None
    return line
#Use readLine like you would input, but make sure to include one parameter - the time to wait in seconds.
print(readLine(3))

Answer 1

如果可以的话，我会把这篇文章作为评论发表。查看datetime模块，http://docs.python.org/3/library/datetime.html -您可以使用datetime.now()和timedelta来完成与上面相同的事情。