查找文件中出现的单词

Question

我正在尝试查找文件中出现的字数。我有一个文本文件(TEST.txt(，文件内容如下：

ashwin programmer india
amith programmer india

我期望的结果是：

{ 'ashwin':1, 'programmer ':2,'india':2, 'amith ':1}

我使用的代码是：

for line in open(TEST.txt,'r'):
    word = Counter(line.split())
    print word

我得到的结果是：

Counter({'ashwin': 1, 'programmer': 1,'india':1})
Counter({'amith': 1, 'programmer': 1,'india':1})

有谁能帮我吗？提前谢谢。

Answer 1

使用Counter的update方法。示例：

from collections import Counter
data = '''
ashwin programmer india
amith programmer india'''
c = Counter()
for line in data.splitlines():
    c.update(line.split())
print(c)

输出：

Counter({'india': 2, 'programmer': 2, 'amith': 1, 'ashwin': 1})

Answer 2

from collections import Counter;
cnt = Counter ();
for line in open ('TEST.txt', 'r'):
  for word in line.split ():
    cnt [word] += 1
print cnt

Answer 3

您对每一行都进行迭代，每次都调用Counter。您希望Counter在整个文件上运行。尝试：

from collections import Counter
with open("TEST.txt", "r") as f:
    # Used file context read and save into contents
    contents = f.read().split()
print Counter(contents)

Answer 4

使用默认dict:

from collections import defaultdict 
def read_file(fname):
    words_dict = defaultdict(int)
    fp = open(fname, 'r')
    lines = fp.readlines()
    words = []
    for line in lines:
        words += line.split(' ')
    for word in words:
        words_dict[word] += 1
    return words_dict

Answer 5

FILE_NAME = 'file.txt'
wordCounter = {}
with open(FILE_NAME,'r') as fh:
  for line in fh:
    # Replacing punctuation characters. Making the string to lower.
    # The split will spit the line into a list.
    word_list = line.replace(',','').replace(''','').replace('.','').lower().split()
    for word in word_list:
      # Adding  the word into the wordCounter dictionary.
      if word not in wordCounter:
        wordCounter[word] = 1
      else:
        # if the word is already in the dictionary update its count.
        wordCounter[word] = wordCounter[word] + 1
print('{:15}{:3}'.format('Word','Count'))
print('-' * 18)
# printing the words and its occurrence.
for  (word,occurance)  in wordCounter.items(): 
  print('{:15}{:3}'.format(word,occurance))

Answer 6

f = open('input.txt', 'r')
data=f.read().lower()
list1=data.split()
d={}
for i in set(list1):
    d[i]=0
for i in list1:
    for j in d.keys():
       if i==j:
          d[i]=d[i]+1
print(d)