我当前有此XAML代码:
<ListView x:Name="listFeedSearch" Margin="-548.856,95.333,0,7.667" HorizontalAlignment="Left" Width="542.5" RenderTransformOrigin="0.5,0.5" ItemsSource="{Binding SearchCollection}">
<ListView.RenderTransform>
<TransformGroup>
<ScaleTransform/>
<SkewTransform/>
<RotateTransform/>
<TranslateTransform/>
</TransformGroup>
</ListView.RenderTransform>
<ListView.View>
<GridView>
<GridViewColumn Width="150" Header="Feed Name" x:Name="listFeedSearchName" DisplayMemberBinding="{Binding FeedName}" />
<GridViewColumn Width="280" Header="Feed Address" x:Name="listFeedSearchAddress" DisplayMemberBinding="{Binding FeedUrl}" />
<GridViewColumn Width="100" Header=" " x:Name="listFeedSearchSelect" />
</GridView>
</ListView.View>
</ListView>
我想做的是让listFeedSearchSelect
在每个记录的单元格中都有一个按钮。
我试图做的是,但没有成功,它所做的只是显示为空单元格:
<GridViewColumn Header=" " Width="100" x:Name="listFeedSearchSelect">
<GridViewColumn.CellTemplate>
<DataTemplate>
<Button Content="Select" />
</DataTemplate>
</GridViewColumn.CellTemplate>
</GridViewColumn>
有人能帮我吗,谢谢。
尝试将模板设置为资源。像这样:
<Window.Resources>
<DataTemplate x:Key="SelectButtonColumnDataTemplate">
<Button Content="Select" Command="{Binding SelectItemCommand}" />
</DataTemplate>
</Window.Resources>
<ListView x:Name="listFeedSearch" HorizontalAlignment="Left" Width="542.5" RenderTransformOrigin="0.5,0.5" ItemsSource="{Binding SearchCollection}">
<ListView.RenderTransform>
<TransformGroup>
<ScaleTransform/>
<SkewTransform/>
<RotateTransform/>
<TranslateTransform/>
</TransformGroup>
</ListView.RenderTransform>
<ListView.View>
<GridView>
<GridViewColumn Width="150" Header="Feed Name" x:Name="listFeedSearchName" DisplayMemberBinding="{Binding FeedName}" />
<GridViewColumn Width="280" Header="Feed Address" x:Name="listFeedSearchAddress" DisplayMemberBinding="{Binding FeedUrl}" />
<GridViewColumn Width="100" Header=" " CellTemplate="{StaticResource SelectButtonColumnDataTemplate}" />
</GridView>
</ListView.View>
</ListView>
如果我只是复制并粘贴你的GridViewColumn
,并且集合有项目,它确实会按预期显示按钮。问题可能出在你的背景上。