注册的接收者包含未初始化的测试对象

Question

首先，我得到一个被测试类的监视实例:

TestedClass testedClass = spy(new TestedClass(Robolectric.buildActivity(Activity.class).create().get());

然后，测试类发生一些变化:testedClass。someString = "whatever"

然后，我模拟向被测试类中注册的广播接收器发送意图:

    ShadowApplication shadowApplication = Robolectric.getShadowApplication();
    Intent intent = new Intent(ConnectivityManager.CONNECTIVITY_ACTION);
    List<BroadcastReceiver> broadcastReceivers = shadowApplication.getReceiversForIntent(intent);
    broadcastReceivers.get(0).onReceive(Robolectric.application, intent);

BroadcastReceiver是在列表中找到的，所以我可以调用onReceive和onReceive事件被触发:

public void onReceive(Context context, Intent intent) {
   Log.i(tag, someString);
}

然而，出现的testdclass对象是一个未初始化的版本，即:someString == ""这不是被监视的那个物体。也许，这是正常的行为，但我想获得我为测试创建的相同实例，而不是并行创建的模拟实例。

Answer 1

这取决于你实例化BroadcastReceiver的方式。

如果使用默认值实例化BroadcastReceiver，则不会执行对BroadcastReceiver的模拟调用

//Class member myBroadcastReceiver
public BroadcastReceiver myBroadcastReceiver = new MyBroadcastReceiver();

但是，如果稍后实例化BroadcastReceiver，它可以正常工作:

public myBroadcastReceiver;
public initializeBroadcastReceiver() {
    myBroadcastReceiver = new MyBroadcastReceiver();
}

这些都是事实，尽管如此，我仍然不知道第一种情况是预期行为还是机器人电气的缺陷。