移动文件的开始字母在powershell, python或其他脚本语言运行的窗口

Question

我需要一个脚本，它可以递归地遍历c:somedir并将文件移动到c:someotherdirx -其中x是文件的起始字母。

有人能帮忙吗?

---

以这个结尾:

import os
from shutil import copy2
import uuid
import random
SOURCE = ".\pictures\"
DEST = ".\pictures_ordered\"
for path, dirs, files in os.walk(SOURCE):
    for f in files:
        print(f)
        starting_letter = f[0].upper()
        source_path = os.path.join(path, f)
        dest_path = os.path.join(DEST, starting_letter)
        if not os.path.isdir(dest_path):
            os.makedirs(dest_path)
        dest_fullfile = os.path.join(dest_path, f)
        if os.path.exists(dest_fullfile):            
            periodIndex = source_path.rfind(".")
            renamed_soruce_path = source_path[:periodIndex] + "_" + str(random.randint(100000, 999999))  + source_path[periodIndex:]
            os.rename(source_path, renamed_soruce_path)
            copy2(renamed_soruce_path, dest_path)            
            os.remove(renamed_soruce_path)
        else:
            copy2(source_path, dest_path)
            os.remove(source_path)`

Answer 1

下面是一个简单的脚本，可以满足您的需求。它不会告诉你它在做什么，如果有两个同名的文件，它只会覆盖旧的文件。

import os
from shutil import copy2
SOURCE = "c:\source\"
DEST = "c:\dest\"
# Iterate recursively through all files and folders under the source directory
for path, dirs, files in os.walk(SOURCE):
    # For each directory iterate over the files
    for f in files:
        # Grab the first letter of the filename
        starting_letter = f[0].upper()
        # Construct the full path of the current source file
        source_path = os.path.join(path, f)
        # Construct the destination path using the first letter of the
        # filename as the folder
        dest_path = os.path.join(DEST, starting_letter)
        # Create the destination folder if it doesn't exist
        if not os.path.isdir(dest_path):
            os.makedirs(dest_path)
        # Copy the file to the destination path + starting_letter
        copy2(source_path, dest_path)

Answer 2

我怀疑这将在PowerShell中工作。

gci -path c:somedir -filter * -recurse |
    where { -not ($_.PSIsContainer) } |
    foreach { move-item -path $_.FullName -destination $_.Substring(0, 1) }

Answer 3

ls c:somedir* -recurse | ? { -not ($_.PSIsContainer)} | mv -destination "C:someotherdir$($_.Name.substring(0,1))" }…-whatif: P

Answer 4

这是Python中的答案，注意警告消息，您可能希望以不同的方式处理覆盖。还要将它保存到根目录下的一个文件中，并在那里运行它，否则您必须将参数更改为os。以及路径是如何连接在一起的

import os
import sys
try:
    letter = sys.argv[1]
except IndexError:
    print 'Specify a starting letter'
    sys.exit(1)
try:
    os.makedirs(letter)
except OSError:
    pass # already exists
for dirpath, dirnames, filenames in os.walk('.'):
    for filename in filenames:
        if filename.startswith(letter):
            src = os.path.join(dirpath, filename)
            dst = os.path.join(letter, filename)
            if os.path.exists(dst):
                print 'warning, existing', dst, 'being overwritten'
            os.rename(src, dst)

Answer 5

当然，我会帮助:看看Python2中的os.path.walk，我相信这只是os。