在Linux上用可滚动的x(时间/水平)轴绘制数据

Question

我想绘制x轴长的数据。如果我画出整个x轴，那么图就会缩小，几乎无法阅读。我在SO上找到了这个答案，它指向下面的scipy/matplotlib代码。但是当我尝试运行上述代码时，我会得到以下错误：

Traceback (most recent call last):
  File "scrollingPlot.py", line 88, in <module>
    app = MyApp()
  File "/usr/lib/python2.7/dist-packages/wx-3.0-gtk2/wx/_core.py", line 8628, in __init__
    self._BootstrapApp()
  File "/usr/lib/python2.7/dist-packages/wx-3.0-gtk2/wx/_core.py", line 8196, in _BootstrapApp
    return _core_.PyApp__BootstrapApp(*args, **kwargs)
  File "scrollingPlot.py", line 82, in OnInit
    self.frame = MyFrame(parent=None,id=-1)
  File "scrollingPlot.py", line 21, in __init__
    self.scroll_range)
  File "/usr/lib/python2.7/dist-packages/wx-3.0-gtk2/wx/_core.py", line 11226, in SetScrollbar
    return _core_.Window_SetScrollbar(*args, **kwargs)
wx._core.PyAssertionError: C++ assertion "sb" failed at ../src/gtk/window.cpp(4754) in SetScrollbar(): this window is not scrollable

PS：也欢迎其他解决方案（最好是python、R或其他简单的多平台解决方案）

PPS：我已经打开了上述错误的问题

Answer 1

您是否考虑过使用matplotlib滑块小部件？

这里有一个小代码，作为的例子

import numpy as np
import matplotlib.pyplot as plt
from matplotlib.widgets import Slider
fig, ax = plt.subplots()
plt.subplots_adjust(bottom=0.25)
t = np.arange(0.0, 100.0, 0.1)
s = np.sin(2*np.pi*t)
l, = plt.plot(t,s)
plt.axis([0, 10, -1, 1])
axcolor = 'lightgoldenrodyellow'
axpos = plt.axes([0.2, 0.1, 0.65, 0.03], facecolor=axcolor)
spos = Slider(axpos, 'Pos', 0.1, 90.0)
def update(val):
    pos = spos.val
    ax.axis([pos,pos+10,-1,1])
    fig.canvas.draw_idle()
spos.on_changed(update)
plt.show()

Answer 2

在R中，这个答案可以帮助您。它会将绘图保存为单独的png，但您可以使用不同的命令更改格式类型。该答案中的相关代码被复制：

 png("wide.png", width = 1e5, height = 500)
 plot((sin(1:10000/100)+rnorm(10000)/5),type='l')
 dev.off()
 #bmp("wide.bmp", width = 1e5, height = 500)
 #plot((sin(1:10000/100)+rnorm(10000)/5),type='l')
 #dev.off()
 #note that the png has a size of 396 KB, while the bmp has 48,830 KB.