- C是某个类的属性成员具有DisplayNameAttribute
- GetDisplayName方法返回指定属性成员的DisplayNameAttribute参数
- .net3.5,Unity3D
我的问题是实现实际上是多余的,因为方法SequenceEqual需要指定的类型参数,所以我应该为每个可能的属性类型实现IF代码块。有什么反射黑魔法可以让我的代码更干净吗?
public class C
{
[DisplayName("M1")]
public List<string> M1 { get; set; }
[DisplayName("M2")]
public List<string> M2 { get; set; }
[DisplayName("M3")]
public string M3 { get; set; }
[DisplayName("M4")]
public List<int> M4 { get; set; }
//There can be many property members with different type
//M5
//...
//...
//M99
}
public void GetCMemberDisplayName()
{
var c = new C
{
M1 = new List<string> {"a"},
M2 = new List<string>(),
M3 = "b",
M4 = new List<int>()
};
var nameOfM1 = GetDisplayName(c, c.M1);//"M1"
var nameOfM2 = GetDisplayName(c, c.M2);//"M2"
var nameOfM3 = GetDisplayName(c, c.M3);//"M3"
}
//EDIT, add another situation, instance and its property member could be input parameters
public string AnotherGetMemberDisplay(object instance, object member)
{
return GetDisplayName(instance, member);
}
private static string GetDisplayName(object instance, object member)
{
var propertyInfos = instance.GetType()
.GetProperties(BindingFlags.Public | BindingFlags.NonPublic | BindingFlags.Instance
| BindingFlags.GetField | BindingFlags.GetProperty)
.FindAll(pi => pi.IsDefined(typeof(DisplayNameAttribute), true));
foreach (var propertyInfo in propertyInfos)
{
var value = propertyInfo.GetValue(instance, null);
//Very nasty code below, need implement all IF code for each type of property member
if (member.GetType() == typeof(List<string>) && value.GetType() == typeof(List<string>))
{
if ((value as List<string>).SequenceEqual(member as List<string>))
{
return (propertyInfo.GetCustomAttributes(true).ToList()
.Find(a => (a as DisplayNameAttribute) != null) as DisplayNameAttribute)
.DisplayName;
}
}
else if (member.GetType() == typeof(List<int>) && value.GetType() == typeof(List<int>))
{
if ((value as List<int>).SequenceEqual(member as List<int>))
{
return (propertyInfo.GetCustomAttributes(true).ToList()
.Find(a => (a as DisplayNameAttribute) != null) as DisplayNameAttribute)
.DisplayName;
}
}
else
{
if (value == member)
{
return (propertyInfo.GetCustomAttributes(true).ToList()
.Find(a => (a as DisplayNameAttribute) != null) as DisplayNameAttribute)
.DisplayName;
}
}
}
throw new Exception("No DisplayNameAttributes Applied.");
}
我建议按照以下几行实现一个方法,以获得所需属性的MemberInfo:
public MemberInfo GetMemberInfo<T>(Expression<Func<T>> memberLambda)
{
var memberExpression = memberLambda.Body as MemberExpression;
if (memberExpression == null)
{
throw new ArgumentException("You must pass a lambda of the form: '() => Class.Member' or '() => object.Member'");
}
return memberExpression.Member;
}
(源自asker的解决方案:以字符串形式获取属性名称(
那么获取属性值就这么简单:
public void GetCMemberDisplayName()
{
var c = new C
{
M1 = new List<string> {"a"},
};
var m1MemberInfo = GetMemberInfo(() => c.M1);
var nameOfM1 = GetDisplayName(m1MemberInfo);
}
private string GetDisplayName(MemberInfo memberInfo)
{
var displayNameAttribute = memberInfo.GetCustomAttribute(typeof(DisplayNameAttribute));
if (displayNameAttribute != null)
{
return displayNameAttribute.DisplayName;
}
else
{
throw new Exception("No DisplayNameAttributes Applied.");
}
}
我避免使用C#代码,因为你最初的帖子被标记为Unity3D,它使用了一个目前不支持C#的编译器。如果您使用的编译器确实支持它,则过程会更简单(不再需要GetMemberInfo方法(:
public void GetCMemberDisplayName()
{
var c = new C
{
M1 = new List<string> {"a"},
};
var nameOfM1 = GetDisplayName(typeof(C), nameof(c.M1));
}
private static string GetDisplayName(Type ownerType, string propertyName)
{
var propertyInfo = ownerType.GetProperty(propertyName);
var displayNameAttribute = propertyInfo.GetCustomAttribute(typeof(DisplayNameAttribute));
if (displayNameAttribute != null)
{
return displayNameAttribute.DisplayName;
}
else
{
throw new Exception("No DisplayNameAttributes Applied.");
}
}