为什么我的方法返回所有数组

Question

我正在编写一个选择您自己的冒险风格的程序。我正在创建三个问题数组q1—q3，每个都有一个数组，另一个数组和一个散列。目标是使用我的question_charge方法遍历数组，然后根据用户的答案返回下一个问题数组。

puts "Please choose an answer to the following questions"
q1 = [["What is your answer to this very first question?"],["A - Option 1","B - Option 2","C - Option 3"],{"A" => q2,"B" => q3, "C" => q3}]
q2 = [["This is the second question, can I have an answer?"],["A - Option 2-1","B - Option 2-2","C - Option 2-3"],{"A" => q3,"B" => q3,"C" => q4}]
q3 = [["Question #3! What is your answer?"],["A - Option 3-1","B - Option 3-2","C - Option 3-3"]]
current_question = q1
def question_charge(current_question)
  x = 0
  puts current_question[x]
  x += 1
  puts current_question[x]
  answer = gets.chomp
  puts "You answered " + answer
  x += 1
  current_question = current_question[x][answer]
end
question_charge(current_question)

有时当我运行这个，我收到以下错误:

(eval):2: undefined local variable or method `q2' for main:Object (NameError)

当它工作时，q3在数组中没有哈希值，就像最后一个问题一样。当我对第一个问题回答'A'时，它多次返回我的所有数组。如果我回答'C'为q3，它返回很好。谁能告诉我如何才能返回我想要的唯一数组，而不会收到一个错误?

Answer 1

当您定义第一个问题时，您的散列如下:

{"A" => q2,"B" => q3, "C" => q3}

，但此时q2和q3都没有定义。您需要在引用q2和q3之前定义它们。

Answer 2

我会试着重写你的方法让它更有意义

def ask_question(current_question)
  question, options, next_question_hash = current_question
  puts question # "What is your answer to this very first question?"
  puts options  # "A - Option 1", ...
  answer = gets.chomp
  puts "You answer #{answer}"
  next_question = next_question_hash[answer]
end

这将提出一个问题，然后返回下一个要回答的问题。