Mule: PGP解密给出错误消息无效PGP消息

Question

实现xml文件的mule pgp加密解密。当解密它时引发错误

ERROR 2015-06-05 12:06:34,192 [Thread-8] org.mule.module.pgp.AbstractTransformPolicy: Invalid PGP message
java.lang.IllegalArgumentException: Invalid PGP message
    at org.mule.module.pgp.DecryptStreamTransformer.initialize(DecryptStreamTransformer.java:79)
    at org.mule.module.pgp.TransformContinuouslyPolicy$ContinuousWork.execute(TransformContinuouslyPolicy.java:60)
    at org.mule.module.pgp.AbstractTransformPolicy$TransformerWork.run(AbstractTransformPolicy.java:109)

我调试了mule pgp包和DecryptStreamTransformer

public void initialize(OutputStream out) throws Exception
    {
        InputStream decodedInputStream = PGPUtil.getDecoderStream(this.toBeDecrypted);
        PGPObjectFactory pgpF = new PGPObjectFactory(decodedInputStream);
        Object o = pgpF.nextObject();
        if (o == null)
        {
            throw new IllegalArgumentException("Invalid PGP message");
        }

PGPObjectFactory返回nextObject为空的原因是什么?在流元素

之后记录消息有效负载

 <decrypt-transformer name="decryptTransformer" strategy-ref="pgpEncryptionStrategy"/>
<logger level="INFO" doc:name=" Message Logger" message="#[payload]"/>
<mulexml:jaxb-xml-to-object-transformer
            jaxbContext-ref="jaxb" doc:name="JAXB-Unmarshaller"
            returnClass="com.generated.Communication" />

负载显示为org.mule.module.pgp.LazyTransformedInputStream@17d80e9。

如何修改此实例为xml，以便mulexml jaxb元素可以将其编组到所需的对象

Answer 1

如源代码所示:

registerSourceType(DataTypeFactory.INPUT_STREAM);

jaxb-xml-to-object-transformer接受任何输入流作为有效的源，所以问题不存在。