将Python代码打开到C++

Question

我正在尝试将Python代码翻译成C++。这是代码：

kernelx = cv2.getStructuringElement(cv2.MORPH_RECT,(2,10))
dx = cv2.Sobel(res,cv2.CV_16S,1,0)
dx = cv2.convertScaleAbs(dx)
cv2.normalize(dx,dx,0,255,cv2.NORM_MINMAX)
ret,close = cv2.threshold(dx,0,255,cv2.THRESH_BINARY+cv2.THRESH_OTSU)
close = cv2.morphologyEx(close,cv2.MORPH_DILATE,kernelx,iterations = 1)
contour, hier = cv2.findContours(close,cv2.RETR_EXTERNAL,cv2.CHAIN_APPROX_SIMPLE)
for cnt in contour:
    x,y,w,h = cv2.boundingRect(cnt)
    if h/w > 5:
        cv2.drawContours(close,[cnt],0,255,-1)
    else:
        cv2.drawContours(close,[cnt],0,0,-1)
close = cv2.morphologyEx(close,cv2.MORPH_CLOSE,None,iterations = 2)
closex = close.copy()

我唯一的问题是这条线路：

if h/w > 5:

我很难找到解决办法。

Answer 1

在C++API中，x、y、h和w是cv::boundingRect():返回的cv::Rect对象的属性

for (size_t i = 0; i < contour.size(); i++)
{
    cv::Mat cnt = contour[i];
    cv::Rect rect = cv::boundingRect(cnt);
    if (rect.height / rect.width > 5)
        // ...
    else
        // ...
}