使用Resque队列进行集成测试或模拟

Question

如何测试这个类?您会将它与Resque集成并检查作业是否被放入队列中，还是会模拟它，如果您会模拟它，您如何避免像示例规范中所示的那样重复代码?

class BookingReminderEnqueuer
  def initialize(user, booking, worker = BookingReminder)
    @user, @booking, @worker = user, booking, worker
  end
  def enqueue
    Resque.enqueue_at(
      remind_user_at,
      @worker,
      booking_id: @booking.id,
      user_id: @user.id
    ) if @booking.remind_user?
  end
  private
  def remind_user_at
    @booking.start_time - 6.hours
  end
end
require 'spec_helper'
describe BookingReminderEnqueuer
  describe "#enqueue" do
    context "when the user should have a reminder" do
      it "enqueues the reminder" do
        booking.stub(:remind_user?) { true }
        Resque.should_receive(:enqueue_at).with(
          booking.start_time - 6.hours,
          BookingReminder,
          booking_id: booking.id,
          user_id: user.id
        ).once
        booking_reminder_enqueuer.enqueue
      end
    end
    context "when the user shouldn't have a reminder" do
      it "does not enqueue the reminder" do
        booking.stub(:remind_user?) { false }
        Resque.should_not_receive(:enqueue_at)
      end
    end
  end
end

Answer 1

我会使用像fakeredis这样的gem来创建一个测试redis db。这将为测试创建一个独立的内存Redis实例，可以在测试运行时清除。然后，您可以验证使用正确的参数对作业进行了正确的排队，而不是模拟enqueue方法(因为使enqueue参数正确工作是该方法的核心)。

    # Gemfile
    group :test do
      gem "rspec"
      gem "fakeredis", :require => "fakeredis/rspec"
    end

    # Spec
    describe BookingReminderEnqueuer
      describe "#enqueue" do
        context "when the user should have a reminder" do
          it "enqueues the reminder" do
            booking.stub(:remind_user?) { true }
            booking_reminder_enqueuer.enqueue
            resque_job = Resque.peek(:queue_name)
            resque_job.should be_present
            # add assertions about job content/scheduling here
          end
        end
        ...
     end
   end