如何在 Spring Soap Webservice Client 中解析 org.xml.sax.SAXExcepti

Question

我按照 http://docs.spring.io/spring-ws/sites/1.5/reference/html/client.html 中提到的步骤使用HTTP传输。我的代码如下：

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.beans.factory.annotation.Value;
import org.springframework.stereotype.Component;
import org.springframework.ws.client.core.WebServiceTemplate;
import java.io.StringReader;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;
import org.springframework.ws.WebServiceMessageFactory;
import org.springframework.ws.transport.WebServiceMessageSender;
@Component
public class blahClient {
@Autowired
private final WebServiceTemplate webServiceTemplate = new                                  WebServiceTemplate();
public void setDefaultUri(String defaultUri) {
    webServiceTemplate.setDefaultUri(defaultUri);
}
// send to an explicit URI
public void customSendAndReceive() {

    StreamSource source = new StreamSource(new StringReader(MESSAGE));
    StreamResult result = new StreamResult(System.out);
    webServiceTemplate.sendSourceAndReceiveToResult(webServiceTemplate.getDefaultUri(),source, result);
    System.out.println(result.toString());
}
private static final String MESSAGE = "<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ser="http://service.blah.internal.blah.com"><soapenv:Header/><soapenv:Body><ser:getblahData><request><caller_id>loginapp</caller_id><content>1067857</content><locale></locale><output>XML, Formatted</output><security_token>vz37ahzcwzakua3z9q2zno66e4xy6wyg8oxh6xn7bordkl</security_token></request></ser:getblahData></soapenv:Body></soapenv:Envelope>";

public static void main(String[] args) {
    IntactwsClient blahClient = new blahClient();
    blahClient .setDefaultUri("http://blah.com/blah/blahService");
    blahClient .customSendAndReceive();
}
}

它给了我这个例外：

Exception in thread "main" org.springframework.ws.soap.client.SoapFaultClientException: org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize.
at org.springframework.ws.soap.client.core.SoapFaultMessageResolver.resolveFault(SoapFaultMessageResolver.java:37)
at org.springframework.ws.client.core.WebServiceTemplate.handleFault(WebServiceTemplate.java:774)
at org.springframework.ws.client.core.WebServiceTemplate.doSendAndReceive(WebServiceTemplate.java:600)
at org.springframework.ws.client.core.WebServiceTemplate.sendAndReceive(WebServiceTemplate.java:537)
at org.springframework.ws.client.core.WebServiceTemplate.doSendAndReceive(WebServiceTemplate.java:492)
at org.springframework.ws.client.core.WebServiceTemplate.sendSourceAndReceiveToResult(WebServiceTemplate.java:436)
at org.springframework.ws.client.core.WebServiceTemplate.sendSourceAndReceiveToResult(WebServiceTemplate.java:421)
at com.blah.internal.blah.service.IntactwsClient.customSendAndReceive(IntactwsClient.java:35)
at com.blah.internal.blah.service.IntactwsClient.main(IntactwsClient.java:59)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:606)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:134)

我已经使用相同的XML消息检查了来自SoapUI的SOAP调用，它工作正常。我无法诊断此错误的原因。我不需要创建一个类并使用从响应中封送的对象，因为我只需要从响应中解析一个值。我希望WebServiceTemplate.sendSourceAndReceiveToResult能够像Soap RestTemplate一样工作，并产生可以解析的响应。

任何帮助将不胜感激。

Answer 1

StreamResult result = new StreamResult(System.out);    
System.out.println(result.toString());

我认为这 2 行是造成异常的原因。在这里阅读

您正在尝试将 StreamResult 对象 直接转换为字符串。相反，您应该将输出流（System.out）使用到字符串中。

试试这个，

System.out.toString();
System.out.println(result.toString());    //Remove this line