导航菜单使用cakePhp树

Question

我使用CakePHP树生成导航菜单。我已经成功地生成了它。现在我需要在导航行为中显示它们。我试过了。它正在工作，但在这段基本代码之后，我不知道该怎么办。。我该如何构建导航。。

更新答案：）：

使用cakeHP树的导航菜单

My HomeController.php

App::uses('AppController', 'Controller');
class HomeController extends AppController {
    var $name='home';
    public function index() {
        $this->layout = "front_end_index";
        $this->loadModel('Category');
        $category_tree = $this->Category->generateTreeList();
        $categories_array = array();
        foreach($category_tree as $k => $v)
        {
            $categories_array[$k] = $this->Category->find('first', array('conditions' => array('Category.id' => $k)));
        }
        $this->set('cat_info',$categories_array);
    }
}

我的分类.ctp

<?php foreach($cat_info as $cat_info) {
      if($cat_info['Category']['parent_id'] == ''){ ?>
         <ul class="menus">
        <li><h4><?php echo $cat_info['Category']['name'] ;?></h4></li>
    <?php } ?>
        </ul>
<?php } ?>

导航阵列示例：

Array
(
    [1] => Array
        (
            [Category] => Array
                (
                    [id] => 1
                    [parent_id] => 
                    [lft] => 1
                    [rght] => 42
                    [name] => My Categories
                    [url] => http://google.com
                )
        )
    [2] => Array
        (
            [Category] => Array
                (
                    [id] => 2
                    [parent_id] => 1
                    [lft] => 2
                    [rght] => 17
                    [name] => Fun
                    [url] => http://google.com
                )
        )
    [3] => Array
        (
            [Category] => Array
                (
                    [id] => 3
                    [parent_id] => 2
                    [lft] => 3
                    [rght] => 8
                    [name] => Sport
                    [url] => http://google.com
                )
        )

Answer 1

在@Isaac Rajaei的引用下执行此操作。尝试-

HomesController.php

App::uses('AppController', 'Controller');
class HomeController extends AppController {
    var $name='home';
    public function index() {
        $this->layout = "front_end_index";
        $this->loadModel('Category');
        $category_tree = $this->Category->find('all');
        $this->set('categories', $category_tree);
    }
}

查看

index.ctp

<?php
    function treeForm(array &$elements, $parentId = 0, $elkey = null) {
        $branch = array();
        foreach ($elements as $key=>$element) {
            if ($element[$elkey]['parent_id'] == $parentId) {
                $children = treeForm($elements, $element[$elkey]['id'], $elkey);
                if ($children) {
                    $element['children'] = $children;
                }
                $branch[$element[$elkey]['id']] = $element;
                unset($elements[$key]);
            }
        }
        return $branch;
    }
    //Build Menu       
    function convertToMenu($arr, $elmkey) {
        echo "<ul>";
        foreach ($arr as $val) {
                if (!empty($val['children'])) {
                        echo "<li>" . $val[$elmkey]['name'];
                        convertToMenu($val['children'], $elmkey);
                        echo "</li>";
                } else {
                        echo "<li>" . $val[$elmkey]['name'] . "</li>";
                }
        }
        echo "</ul>";
    }

        $menuTree = treeForm($categories, 0, 'Category'); // Preparing $categories.
        convertToMenu($menuTree, 'Category');// changing to list, you can add <a> inside it.
?>

Answer 2

定制后，我已经用@fazal和@Isaac Rajaei的解决方案解决了我的问题。希望这对寻求答案的SO有充分的帮助。：）

HomesController.php

 <?php
    App::uses('AppController', 'Controller');
    class HomeController extends AppController {
        var $name='home';
        public function index() {
            $this->layout = "front_end_index";
            $this->loadModel('Category');
            $category_tree = $this->Category->find('threaded');     
            $this->set('categories', $category_tree);
        }
    }

类别.ctp

function convertToMenu($arr, $elmkey) {
        echo "<ul class='menus'>";
        foreach ($arr as $val) {
                if (!empty($val['children'])) {
                        echo "<li>" . $val[$elmkey]['name'];
                        convertToMenu($val['children'], $elmkey);
                        echo "</li>";
                } else {
                        echo "<li><h4>" . $val[$elmkey]['name'] . "</h4></li>";
                }
        }
        echo "</ul>";
    }

 convertToMenu($categories, 'Category');// changing to list, you can add <a> inside it.

Answer 3

对不起，我在键入答案时犯了一些错误。我应该在这里回答。

以前的treeForm方法不是用0生成所有的父id，我更改了如下代码：

控制器：

$categories = $this->Category->findAllByParentId(0);
$data = array(
        'categories' => $categories,
    );
    $this->set(compact('data'));

treeForm方法：

function treeForm(array &$elements, $parentId = 0, $elkey = null) {
    $branch = array();
    foreach ($elements as $key=>$element) {
        if ($element[$elkey]['parent_id'] == $parentId) {
            //adjustment was here, re-find again all children data, so it will work
            //recursively method
            $findChildren = ClassRegistry::init($elkey)->findAllByParentId($element[$elkey]['id']);
            $children = $this->treeForm($findChildren, $element[$elkey]['id'], $elkey);
            if ($children) {
                $element['children'] = $children;
            }
            $branch[$element[$elkey]['id']] = $element;
            unset($elements[$key]);
        }
    }
    return $branch;
}