ID 未在重写规则中传递

Question

我在使用 .htaccess 时遇到问题。"重新写入"规则如下所示。

RewriteRule ^user/([a-z]+)/?$ user.php?id=$1

传入网址 ： http://abhimanyu.localhost.com/user/home/它重定向到用户.php但我没有得到 ID。例如$id= $_GET['id'];

知道为什么吗???

仅供参考，重写日志

127.0.0.1 - - [08/May/2011:23:38:35 +051800] [abhimanyu.localhost.com/sid#b8b34860][rid#b8d34d28/subreq]
(1) [perdir
/home/administrator/public_html/abhimanyu/]
pass through
/home/administrator/public_html/abhimanyu/user.php
127.0.0.1 - - [08/May/2011:23:38:35 +051800] [abhimanyu.localhost.com/sid#b8b34860][rid#b8d21ce0/initial]
(3) [perdir
/home/administrator/public_html/abhimanyu/]
add path info postfix:
/home/administrator/public_html/abhimanyu/user.php
-> /home/administrator/public_html/abhimanyu/user.php/home
127.0.0.1 - - [08/May/2011:23:38:35 +051800] [abhimanyu.localhost.com/sid#b8b34860][rid#b8d21ce0/initial]
(3) [perdir
/home/administrator/public_html/abhimanyu/]
strip per-dir prefix:
/home/administrator/public_html/abhimanyu/user.php/home
-> user.php/home
127.0.0.1 - - [08/May/2011:23:38:35 +051800] [abhimanyu.localhost.com/sid#b8b34860][rid#b8d21ce0/initial]
(3) [perdir
/home/administrator/public_html/abhimanyu/]
applying pattern '^user/([a-z]+)/?$'
to uri 'user.php/home'
127.0.0.1 - - [08/May/2011:23:38:35 +051800] [abhimanyu.localhost.com/sid#b8b34860][rid#b8d21ce0/initial]
(1) [perdir
/home/administrator/public_html/abhimanyu/]
pass through
/home/administrator/public_html/abhimanyu/user.php
127.0.0.1 - - [08/May/2011:23:38:35 +051800] [abhimanyu.localhost.com/sid#b8b34860][rid#b8d2cd08/subreq]
(1) [perdir
/home/administrator/public_html/abhimanyu/]
pass through
/home/administrator/public_html/abhimanyu/home

Answer 1

试试这个：

RewriteRule ^user/([a-z]+)$ user.php?id=$1 [NC]

Answer 2

我不知道您是在/user/之后还是在/user/home之后立即捕获字符串。如果需要同时捕获两者，请尝试以下操作：

^user/([a-z]+)/(.+)$

您可以使用 $1 访问用户后的第一个字符串，并使用 $2 访问第二个字符串。

Answer 3

尝试禁用MultiViews选项。