我在Orders表中有一个日期列SLA_Date。
我的SLA_Date应该不包括周末(周六和周日(。工作日的数据应单独显示。
如何在SQL中做到这一点？
您只需要添加以下过滤器：
WHERE TO_CHAR(date_column, 'DY','NLS_DATE_LANGUAGE=AMERICAN') NOT IN ('SAT', 'SUN')
您的查询看起来像：
SELECT SLA_Date
FROM orders
WHERE TO_CHAR(SLA_Date, 'DY','NLS_DATE_LANGUAGE=AMERICAN') NOT IN ('SAT', 'SUN')
例如(WITH子句仅用于构建测试用例(，下面的查询仅显示从1st May 2015到31st May 2015的工作日(即不包括周六和周日(：
SQL> WITH DATA AS
2 (SELECT to_date('05/01/2015', 'MM/DD/YYYY') date1,
3 to_date('05/31/2015', 'MM/DD/YYYY') date2
4 FROM dual
5 )
6 SELECT date1+LEVEL-1 the_date,
7 TO_CHAR(date1+LEVEL-1, 'DY','NLS_DATE_LANGUAGE=AMERICAN') day
8 FROM DATA
9 WHERE TO_CHAR(date1+LEVEL-1, 'DY','NLS_DATE_LANGUAGE=AMERICAN')
10 NOT IN ('SAT', 'SUN')
11 CONNECT BY LEVEL <= date2-date1+1;
THE_DATE DAY
--------- ---
01-MAY-15 FRI
04-MAY-15 MON
05-MAY-15 TUE
06-MAY-15 WED
07-MAY-15 THU
08-MAY-15 FRI
11-MAY-15 MON
12-MAY-15 TUE
13-MAY-15 WED
14-MAY-15 THU
15-MAY-15 FRI
18-MAY-15 MON
19-MAY-15 TUE
20-MAY-15 WED
21-MAY-15 THU
22-MAY-15 FRI
25-MAY-15 MON
26-MAY-15 TUE
27-MAY-15 WED
28-MAY-15 THU
29-MAY-15 FRI
21 rows selected.
SQL>
有关详细示例，请参阅生成日期、月份名称、周编号、两个日期之间的日期
您可以尝试以下条件来过滤数据：
WHERE to_char (SLA_Date, 'FmDay', 'nls_date_language=english') <> 'Saturday'
AND to_char (SLA_Date, 'FmDay', 'nls_date_language=english') <> 'Sunday'
select *
from orders
where TRUNC (thing) - TRUNC (thing, 'IW') between 0 and 4;
http://sqlfiddle.com/#！4/db891/1