我怎样才能避开垃圾?

Question

strcpy(home,"");
    for(j=del1;j<del2;j++){
    home[ strlen(home) ] = word[j];
printf("your house is %s",home);

但是我得到了垃圾。我试着这样做:

strcat(word[j],home);

但是当我运行它时它没有工作

我正在尝试编写一个简单的程序来从文件中写入/读取单词:

WRITTE

:

fp = fopen ( "houses.txt", "a" );
fprintf(fp,"%s&",home);
fclose ( fp );
printf(" Inserted elementn");

读:

char c, home[50],word[100];
strcpy(home,"");
int i=0,del1=0,del2=0,j;
FILE *fp;
fp = fopen ( "houses.txt", "r" );
while (c!=EOF)
{
    c=getc(fp);
    word[i]=c;
    i=i+1;
    if (c=='&')
    {
        del2=i-1;
        strcpy(home,"");
        for(j=del1;j<del2;j++)
        {
            strcat(word[i], home);// OR home[ strlen(home) ] = word[j];
        }
        del1=del2;
        printf("%s n",home);
    }
}
fclose ( fp );

Answer 1

如果您要做的只是打印文件中每个&分隔的字符串，那么您应该将字符读入缓冲区，直到找到&。然后，将&替换为，打印缓冲区，然后将插入点重置到缓冲区的开始位置。类似这样(注意没有任何错误检查)。

#include <stdio.h>
int main(int argc, char **argv)
{
    char home[50];
    int i, c;
    FILE *fp;
    fp = fopen ("houses.txt", "r");
    i = 0;
    while ((c = fgetc(fp)) != EOF) {
        if (c == '&') {
            home[i] = '';
            puts(home);
            i = 0;
        }
        else {
            home[i++] = c;
        }
    }
    fclose ( fp );
    return 0;
}

或者，您可以使用fscanf来为您查找&:

#include <stdio.h>
int main(int argc, char **argv)
{
    char home[50];
    FILE *fp;
    fp = fopen ("houses.txt", "r");
    while (fscanf(fp, "%[^&]&", home) == 1) {
        puts(home);
    }
    fclose ( fp );
    return 0;
}