你好,
org.springframework.dao.DataIntegrityViolationException: could not insert: [com.entity.payment.BPaymentItem]; SQL [insert into sc.PHistoryItem (amount, beneficiaryAccNo, beneficiaryBankCode, beneficiaryBankName, beneficiaryRef2, billCode, branchId, chargeTo, cibRefNo, cifId, collectionAccountNo, companyId, companyName, createdHostDateTime, currentStatus, customerCategoryCharges, customerCategoryCode, customerCategoryId, customerCategoryName, description, errorCode, errorMessage, fromAccountName, fromAccountNo, fromAccountType, fromFavourite, gst, gstAmount, gstInclusive, gstName, gstRate, gstRefNo, gstTaxCode, hostRefNo, nbpsBillerCode, nbpsBillerName, nbpsReferenceNo, nbpsRrn2, nbpsRtn, nbpsSystemReferenceNo, notifyRetryCount, paymentDate, paymentHistoryId, processDate, promotionCharges, promotionCode, promotionId, promotionName, ref1, ref2, reference, rejectReason, remittanceStatus, remittanceTo, rfi, rrnInfo, rtTrxCode, rtnStatus, serviceCharge, serviceChargeCode, serviceChargeGLAcct, serviceChargeId, serviceChargeName, servicePackageCode, servicePackageId, servicePackageName, serviceType, showTerm, smsCharges, smsGst, smsGstAmount, smsGstInclusive, smsGstRate, smsGstTaxCode, toAccountName, toAccountNo, toAccountType, transferType, type, validateSig, approvalItemId) values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)]; nested exception is org.hibernate.exception.DataException: could not insert: [com.entity.payment.BPaymentItem]
at org.springframework.orm.hibernate3.SessionFactoryUtils.convertHibernateAccessException(SessionFactoryUtils.java:642) ~[org.springframework.orm-3.0.4.RELEASE.jar:3.0.4.RELEASE]
Caused by: com.ibm.db2.jcc.am.SqlDataException: DB2 SQL Error: SQLCODE=-302, SQLSTATE=22001, SQLERRMC=null, DRIVER=3.63.123
at com.ibm.db2.jcc.am.fd.a(fd.java:671) ~[db2jcc.jar:na]
...
SQLSTATE 22001是由Character数据引起的,发生了右截断;例如,更新或插入值是一个对于列太长的字符串,或者不能将日期时间值分配给宿主变量,因为它太小。
但是,有没有办法检查是哪一列导致了这个错误?
无法从此错误消息中确定导致问题的列。但基于此错误:SQLERRMC=null。您的数据试图插入null值,或者您的列不接受null,或者您没有传递正确类型的null。
如果你使用的是这样一个预先准备好的语句,那么要插入一个null,你需要指定它
String query = "insert into table_temp(col1,col2) values(?,?)";
pstmt = con.prepareStatement(query);
pstmt.setString(1, "a");
pstmt.setNull(2, java.sql.Types.NULL);