在多维数组PHP中的所有键中进行搜索

Question

我想在多维数组中的所有键中搜索特定字符串。我只需要弄清楚它是否存在，仅此而已。我想知道访问者的IP是否存在于任何阵列中。

有没有php函数或方法可以用来实现这一点，我尝试过的每一个都会返回false。(in_array，array_search，array_filter(

我希望避免循环遍历每个键和一组值。

示例阵列

Array
(
    [21] => Array
        (
            [click_id] => 21
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 17:56:57
            [url_id] => 11
        )
    [22] => Array
        (
            [click_id] => 22
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 17:57:05
            [url_id] => 12
        )
    [23] => Array
        (
            [click_id] => 23
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 18:42:42
            [url_id] => 10
        )
)

感谢

Answer 1

我可以想象一种你不必循环(至少你自己(的方法：

$term = preg_quote('109.148.183.1', '~'); // lets make sure it's safe
$result = array_map('unserialize', preg_filter('~' . $term . '~', '$0', array_map('serialize', $data)));
echo '<pre>';
print_r($result);
echo '</pre>';

使用您的示例数据：

$data = array
(
    21 => array
    (
        'click_id' => 21,
        'ip_addr' => '109.148.183.1',
        'dtime' => '2011-04-28 17:56:57',
        'url_id' => 11,
    ),
    22 => array
    (
        'click_id' => 22,
        'ip_addr' => '109.148.183.1',
        'dtime' => '2011-04-28 17:57:05',
        'url_id' => 12,
    ),
    23 => array
    (
        'click_id' => 23,
        'ip_addr' => '109.148.183.1',
        'dtime' => '2011-04-28 18:42:42',
        'url_id' => 10,
    ),
);

它正确地返回值为109.148.183.1:的密钥(21、22和23(

Array
(
    [21] => Array
        (
            [click_id] => 21
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 17:56:57
            [url_id] => 11
        )
    [22] => Array
        (
            [click_id] => 22
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 17:57:05
            [url_id] => 12
        )
    [23] => Array
        (
            [click_id] => 23
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 18:42:42
            [url_id] => 10
        )
)

---

由于这是一个正则表达式，我们可以进行更强大的搜索，例如搜索所有具有奇数秒数的2011-04-28日期：

$term = '2011-04-28 [0-9]{2}:[0-9]{2}:[0-9][13579]';
$result = array_map('unserialize', preg_filter('~' . $term . '~', '$0', array_map('serialize', $data)));
echo '<pre>';
print_r($result);
echo '</pre>';

输出：

Array
(
    [21] => Array
        (
            [click_id] => 21
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 17:56:57
            [url_id] => 11
        )
    [22] => Array
        (
            [click_id] => 22
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 17:57:05
            [url_id] => 12
        )
)

Answer 2

永远无法避免循环：-(

function search($array, $searchString){
   foreach($array as $key=>$val){
        if(in_array($searchString, $val)) return true;
   }
   return false;
}
//use it like so:
if(search($array, '109.148.183.1')){/*do something*/}

Answer 3

$matching_keys = array();
function search ($item, $key) {
  global $matching_keys();
  // do your testing here, stuff matches in $matching_keys, or however you wanna do it
}
array_walk_recursive($array, 'search');

或者，您可以编写自己的递归函数，避免使用全局函数。这只是最直接的方式。