如果第二个数字是第一个数字的倍数，则此程序应返回True。如果不是，则为False，并且应该执行三次。输出只是给出第一个正确答案。如何获得包含变量f和g的返回？
或者，如果这不是正确的做法，那又是什么呢？我需要让它们都来自同一种方法，否则我只会制作更多的方法，但事实上我被难住了。
非常感谢您的帮助。对不起我的套子。
import java.util.Scanner;
public class Numbers3 {
// starts execution of java application
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int firstnumber = 0; // initialize integer first number
int secondnumber = 0; // initialize integer second number
int third = 0;
int fourth = 0;
int fifth = 0;
int sixth = 0;
// First input field
System.out.print("Input first number ");
firstnumber = input.nextInt();
// Second input field
System.out.print("Input second number ");
secondnumber = input.nextInt();
// makes result equal the Boolean output of isMultiple method
Boolean result = isMultiple(firstnumber, secondnumber, third, fourth,
fifth, sixth);
System.out.println("" + result);
System.out.println();
System.out.print("input first number ");
third = input.nextInt();
System.out.print("input second number ");
fourth = input.nextInt();
System.out.println("" + result);
System.out.println();
System.out.print("input first number ");
fifth = input.nextInt();
System.out.print("input second number ");
sixth = input.nextInt();
System.out.println("" + result);
}
// creates method using the user input
public static Boolean isMultiple(int a, int b, int w, int x, int y, int z) {
Boolean e = null; // initialize boolean
Boolean f = null;
Boolean g = null;
if (a % b != 0) // what the function does if the result is not 0
e = false;
// what the function will do if the function does result in 0
if (a % b == 0)
e = true;
if (w % x != 0)
f = false;
if (w % x == 0)
f = true;
if (y % z != 0)
g = false;
if (y % z == 0)
g = true;
return e;
// returns e as the result of this method.
} // end program
} // end class
对于每次运行，都有两个输入
目标：使用isMultiple()检查第一个输入是否是第二个输入的倍数。
要运行它3次(或任意#次(，请将repeating code放入for循环中
#重复循环的次数存储在常量NUM_RUNS中。
代码：
import java.util.Scanner;
public class Numbers3 {
private static final int NUM_RUNS = 3;
// starts execution of java application
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
for(int i = 0; i < NUM_RUNS; i++) {
// First input field
System.out.print("Input first number: ");
int firstNumber = input.nextInt();
// Second input field
System.out.print("Input second number: ");
int secondNumber = input.nextInt();
System.out.printf("%d is a multiple of %d: %s%n%n",
firstNumber, secondNumber,
isMultiple(firstNumber, secondNumber));
}
}
public static boolean isMultiple(int a, int b) {
return (a % b == 0);
}
} // end class
输入/输出示例：
Input first number: 8
Input second number: 2
8 is a multiple of 2: true
Input first number: 7
Input second number: 3
7 is a multiple of 3: false
Input first number: 18
Input second number: 6
18 is a multiple of 6: true
我不确定f和g是怎么回事，但这里有一个程序要求两个数字，三次，如果第二个是第一个的倍数，则打印true或false：
public static void main(String[] args) throws IOException {
BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
for (int i = 0; i < 3; i++) {
System.out.print("Enter first number : ");
int first = Integer.parseInt(reader.
System.out.print("Enter second number : ");
int second = Integer.parseInt(reader.readLine());
boolean secondMultipleOfFirst = second % first == 0;
System.out.println(secondMultipleOfFirst);
}
}
我也知道你的方法出了什么问题。您计算的值是正确的，但每次都返回e，这是第一个结果。因此，接下来的两个输入给出了第一个结果。
使用循环，而不是设置更多的方法或查看返回哪个值的方法。这样，您可以取两个值，看看n2是否是n1的倍数。
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package dump_me;
import java.util.Scanner;
public class Numbers3
{
// starts execution of java application
public static void main( String[] args)
{
Scanner input = new Scanner (System.in );
int firstnumber = 0; // initialize integer first number
int secondnumber = 0; // initialize integer second number
// makes result equal the Boolean output of isMultiple method
String loop = "N";
do{
// First input field
System.out.print("Input first number ");
firstnumber = input.nextInt();
// Second input field
System.out.print("Input second number ");
secondnumber = input.nextInt();
Boolean result = isMultiple(firstnumber, secondnumber);
System.out.println("" + result );
System.out.println();
System.out.println("Do you wan to continue? Press y to continue or n to exit" );
loop = input.next();
}while(loop.equalsIgnoreCase("y"));
}
// creates method using the user input
public static Boolean isMultiple( int a, int b)
{
if(a==0 || b==0)
{
return false;
}
else
{
if(b % a ==0)
{
return true;
}
else
{
return false;
}
}
// returns e as the result of this method.
} // end program
} // end class
用户输入已被放入循环中。此程序将接受用户输入并检查值。