actionscript 3-如何将变量传递给新的孩子?[闪光AS3]



代码很好地说明了这个问题,我已经删除了所有不相关的内容。

游戏开始时创建2-4个亲属

function createInitialKinsmen()
{
    for (var k:int = 1; k < 3 + Math.round(Math.random() * 2; k++)
    {
        if (k == 1)
        {
            createKinsmen(0);
            trace ("player");
        }
        else
        {
            createKinsmen(1);
            trace ("starting kinsmen");
        }
    }
}

亲属创建功能

function createKinsmen(arrivalTypeVar:int)
{
    var newKinsmen = new kinsmen;
    listPanel.kinsmenDivider.addChild(newKinsmen);
    totalKinsmen++;
    totalKinsmenAlive++;
    newKinsmen.name = "kinsmen" + totalKinsmen;
    newKinsmen.arrivalType = arrivalTypeVar;
}

亲属类

public class kinsmen extends MovieClip
{
    var arrivalType:int;
    function kinsmen()
    {
        trace(this.name);
        if (this.arrivalType = 0)
        {
            trace("player");
        }
        if (this.arrivalType = 1)
        {
            trace("starting kinsmen");
        }
    }
}

输出应该是:

kinsmen1
player
player
kinsmen2
starting kinsmen
starting kinsmen
kinsmen3
starting kinsmen
starting kinsmen
kinsmen4
starting kinsmen
starting kinsmen

但取而代之的是:

kinsmen1
player
player
kinsmen2
player
starting kinsmen
kinsmen3
player
starting kinsmen
kinsmen4
player
starting kinsmen

这意味着arrivalType变量没有被传递。它似乎是可以传递的硬编码变量,因此目前我在亲属移动中有一个阿尔法为0的正方形,它的x位置决定了构造函数中rrivalType的值,但这肯定不是一个好的做法,有更好的方法吗?

我认为您只想修改kinsmen类的构造函数,以接受arrivalTypename的参数。

您当前正在做的是构建一个新的kinsmen对象,然后在该对象上设置arrivalTypename。因此,当构造函数代码运行时,arrivalTypeint的默认值,即0。

kinsmen类中这样修改构造函数:

function kinsmen(arrivalType:int, name:String)
{
    this.name = name;
    this.arrivalType = arrivalType;
    if (this.arrivalType == 0)
    {
        trace("player");
    }
    if (this.arrivalType == 1)
    {
        trace("starting kinsmen");
    }
}

并修改createKinsmen()函数,使其将arrivalType的值传递给构造函数方法,而不是在创建对象后设置arrivalTypename

function createKinsmen(arrivalTypeVar:int)
{
    totalKinsmen++;
    totalKinsmenAlive++;
    var newKinsmen = new kinsmen(arrivalTypeVar, "kinsmen" + totalKinsmen);
    listPanel.kinsmenDivider.addChild(newKinsmen);
}

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