我有带测试程序的LinkedList。正如您在该程序中看到的,我将一些学生添加到列表中。我可以删除它们。如果我选择s1,s2,s3或az s4删除,一切都运行正常,我的列表打印正确,元素数量信息正确。但是如果我删除最后一个元素(在这种情况下- 5)关于元素数量的信息仍然是正确的,但是这个元素仍然被打印出来。为什么会这样呢?我错在哪里?
public class Lista implements List {
private Element head = new Element(null); //wartownik
private int size;
public Lista(){
clear();
}
public void clear(){
head.setNext(null);
size=0;
}
public void add(Object value){
if (head.getNext()==null) head.setNext(new Element(value));
else {
Element last = head.getNext();
//wyszukiwanie ostatniego elementu
while(last.getNext() != null)
last=last.getNext();
// i ustawianie jego referencji next na nowowstawiany Element
last.setNext(new Element(value));}
++size;
}
public Object get(int index) throws IndexOutOfBoundsException{
if(index<0 || index>size) throw new IndexOutOfBoundsException();
Element particular = head.getNext();
for(int i=0; i <= index; i++)
particular = particular.getNext();
return particular.getValue();
}
public boolean delete(Object o){
if(head.getNext() == null) return false;
if(head.getNext().getValue().equals(o)){
head.setNext(head.getNext().getNext());
size--;
return true;
}
Element delete = head.getNext();
while(delete != null && delete.getNext() != null){
if(delete.getNext().getValue().equals(o)){
delete.setNext(delete.getNext().getNext());
size--;
return true;
}
delete = delete.getNext();
}
return false;
}
public int size(){
return size;
}
public boolean isEmpty(){
return size == 0;
}
public IteratorListowy iterator() {
return new IteratorListowy();
}
public void wyswietlListe() {
IteratorListowy iterator = iterator();
for (iterator.first(); !iterator.isDone(); iterator.next())
{
System.out.println(iterator.current());
}
System.out.println();
}
public void infoOStanie() {
if (isEmpty()) {
System.out.println("Lista pusta.");
}
else
{
System.out.println("Lista zawiera " + size() + " elementow.");
}
}
private static final class Element{
private Object value;
private Element next; //Referencja do kolejnego obiektu
public Element(Object value){
setValue(value);
}
public void setValue(Object value) {
this.value = value;
}
public Object getValue() {
return value;
}
//ustawia referencję this.next na obiekt next podany w atgumencie
public void setNext(Element next) {
if (next != null)
this.next = next;
}
public Element getNext(){
return next;
}
}
private class IteratorListowy implements Iterator{
private Element current;
public IteratorListowy() {
current = head;
}
public void next() {
current = current.next;
}
public boolean isDone() {
return current == null;
}
public Object current() {
return current.value;
}
public void first() {
current = head.getNext();
}
}
}
测试public class Program {
public static void main(String[] args) {
Lista lista = new Lista();
Iterator iterator = lista.iterator();
Student s1 = new Student("Kowalski", 3523);
Student s2 = new Student("Polański", 45612);
Student s3 = new Student("Karzeł", 8795);
Student s4 = new Student("Pałka", 3218);
Student s5 = new Student("Konowałek", 8432);
Student s6 = new Student("Kłopotek", 6743);
Student s7 = new Student("Ciołek", 14124);
lista.add(s1);
lista.add(s2);
lista.add(s3);
lista.add(s4);
lista.add(s5);
lista.wyswietlListe();
lista.delete(s5);
lista.wyswietlListe();
lista.infoOStanie();
lista.clear();
lista.infoOStanie();
}
}
问题是您的setNext(Element next)
方法不设置任何如果next == null
。这就是列表最后一个元素的情况。
所以当你调用delete.setNext(delete.getNext().getNext());
时,实际上没有设置任何东西,因为delete.getNext().getNext()
是null
!
删除setNext
中的if (next != null)
条件,它将工作