如何以更有效和优雅的方式从下面的查询中获取MY_LATEST_INSERTED_NUMBER_BASING_ON_MY_DATE_COLUMN_FOR_ID_CONTEXT ?
SELECT MAX(MY_DATE_COLUMN),
ID,
listagg(SOME_COLUMN, '') within GROUP (ORDER BY MY_DATE_COLUMN),
SUBSTR(
listagg(MY_NUMBER, ';') within GROUP (ORDER BY MY_DATE_COLUMN DESC),
1,
instr(
listagg(MY_NUMBER, ';') within GROUP (ORDER BY MY_DATE_COLUMN DESC),'-') - 1
) as MY_LATEST_INSERTED_NUMBER_BASING_ON_MY_DATE_COLUMN_IN_ID_CONTEXT
FROM MY_TABLE
GROUP BY ID;
如果我理解正确的话,您想要keep
:
SELECT MAX(MY_DATE_COLUMN), ID,
listagg(SOME_COLUMN, '') within GROUP (ORDER BY MY_DATE_COLUMN),
max(MY_LATEST_INSERTED_NUMBER_BASING_ON_MY_DATE_COLUMN_IN_ID_CONTEXT)
keep (dense_rank first order by MY_DATE_COLUMN DESC)
FROM MY_TABLE
GROUP BY ID;