下面的代码使用g++-4.8编译,但使用clang 3.4时不能编译。
#include <type_traits>
#include <functional>
struct A {
template <typename Continuation>
bool operator()(
//const Continuation & continuation
Continuation continuation
) const {
return true;
}
};
bool f(A) {
return true;
}
auto g(A a) ->
typename std::result_of<A(
decltype(std::bind(f, a)))>::type
{
auto continuation = std::bind(f, a);
return a(continuation);
}
int main(int argc, char ** argv) {
A a;
g(a);
}
c++ -4.8 -std=c++0x test. cpp# OK
clang++ -std=c++0x test.cpp
test.cpp:22:38: error: no type named 'type' in 'std::result_of<A (std::_Bind<bool (*(A))(A)>)>'
decltype(std::bind(f, a)))>::type
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~
1 error generated.
当您取消注释已注释的行并注释下一行时,代码将同时在clang和g++上编译。
result_of在decltype之前,您应该像这样简化语法:
auto g(A a) -> decltype( std::declval<A>()( std::bind(f, a) ) )