强制执行密码要求

Question

我想检查用户是否成功满足以下要求：

• 密码至少有8个字符
• 由一个资本&一个小写字母

我该怎么做？

我正在使用以下PHP脚本：

if ( strlen( $password ) < 8 ) {
     false
} else {
   if ( preg_match( "/[^0,9]/", $password ) ) {
     // how to check the upper case and lower case
   }
}

Answer 1

您可以使用正则表达式：

if (!preg_match('/^(?=[a-z])(?=[A-Z])[a-zA-Z]{8,}$/', $password))
{
    //error
}

Answer 2

使用preg_match("/[A-Z]/")和preg_match("/[a-z]/")

Answer 3

if( strlen($password) < 8 ) {
     return false;
}
if(preg_match("/[^0,9]/", $password)) {
     how to check the upper case and lower case
}
if($password == strtoupper($password) || $password == strtolower($password)){
//pass fails because its either all upcase, or lowercase
}

Answer 4

您可以使用密码排名技术：

$x = "a12ASD!@#$";
$rank = Array();

$rank['length'] = strlen($x);
$matches = Array();
preg_match_all("/([a-z]+)/", $x, $matches);
$rank['lowercase'] = strlen(implode('', $matches[0]))/count($matches[0]);
$matches = Array();
preg_match_all("/([A-Z]+)/", $x, $matches);
$rank['uppercase'] = strlen(implode('', $matches[0]))/count($matches[0]);
$matches = Array();
preg_match_all("/([0-9]+)/", $x, $matches);
$rank['numbers'] = strlen(implode('', $matches[0]))/count($matches[0]);
$matches = Array();
preg_match_all("/([^a-zA-Z0-9]+)/", $x, $matches);
$rank['symbols'] = strlen(implode('', $matches[0]))/count($matches[0]);

echo "<pre>";
var_dump($rank);
echo "</pre>";

Answer 5

if (
  strlen($password) >= 8) &&
  preg_match('/[A-Z]/', $password) > 0 &&
  preg_match('/[a-z]/', $password) > 0 )
{
  /* Password validation passes, do stuff. */
}
else {
  /* Password validation fails, show error. */
}

Answer 6

您可以使用trim，它实际上比regexp 快得多

if ( trim( $password, 'a..z') != '' && trim( $password, 'A..Z') != '' && strlen($password) >= 8 )
{
  /* Password validation passes, do stuff. */
}
else {
  /* Password validation fails, show error. */
}

Answer 7

要验证用户是否满足php端的密码要求，如下所示。

// Given password
$password = 'user-input-pass';
// Validate password strength
$uppercase = preg_match('@[A-Z]@', $password);
$lowercase = preg_match('@[a-z]@', $password);
$number    = preg_match('@[0-9]@', $password);
$specialChars = preg_match('@[^w]@', $password);
if(!$uppercase || !$lowercase || !$number || !$specialChars || mb_strlen($password) < 8) {
    echo 'Password should be at least 8 characters in length and should include at least one upper case letter, one number, and one special character.';
}else{
    echo 'Strong password.';
}

我给你的剧本；检查长度、复杂性（包含数字、大写、小写，如果需要特殊字符）

Answer 8

preg_match('/[a-z]/', $password) && preg_match('/[A-A]/', $password)

Answer 9

此函数允许您通过使用preg_replace:中的count参数计数出现次数来设置最低要求

  function password_validate($password, $min_length=8, $min_lowercases=1, $min_uppercases=1, $min_numbers=1, $min_specials=0) {
    preg_replace('#[a-z]#', '', $password, -1, $lowercases);
    preg_replace('#[A-Z]#', '', $password, -1, $uppercases);
    preg_replace('#[0-9]#', '', $password, -1, $numbers);
    preg_replace('#[^w]#', '', $password, -1, $specials);
    return (mb_strlen($password) >= $min_length && $lowercases >= $min_lowercases && $uppercases >= $min_uppercases && $numbers >= $min_numbers && $specials >= $min_specials);
  }

它可以这样使用：

  if (!password_validate($new_password)) {
    echo 'Password did not meet requirements';
  }

或通过要求：

  if (!password_validate($new_password, 6, 1, 0, 0, 0)) {
    echo 'Password did not meet requirements';
  }