我正在学习Spring 4.0 + Hibernate 4.3集成,我对这两种技术都很陌生。在解出之前的式子后会出现错误。谁来指导我成功完成这个任务。
中
<?xml version='1.0' encoding='UTF-8' ?>
<!-- was: <?xml version="1.0" encoding="UTF-8"?> -->
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-4.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd">
<!--bean id="propertyConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"
p:location="/WEB-INF/jdbc.properties" />
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource"
p:driverClassName="${jdbc.driverClassName}"
p:url="${jdbc.url}"
p:username="${jdbc.username}"
p:password="${jdbc.password}" /-->
<!-- ADD PERSISTENCE SUPPORT HERE (jpa, hibernate, etc) -->
</beans>
dispatcher-servlet.xml
<?xml version='1.0' encoding='UTF-8' ?>
<!-- was: <?xml version="1.0" encoding="UTF-8"?> -->
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-4.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd">
<bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>
<context:component-scan base-package="com.controller"/>
<mvc:annotation-driven />
<!--
Most controllers will use the ControllerClassNameHandlerMapping above, but
for the index controller we are using ParameterizableViewController, so we must
define an explicit mapping for it.
-->
<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="mappings">
<props>
<prop key="index.htm">indexController</prop>
</props>
</property>
</bean>
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:prefix="/WEB-INF/jsp/"
p:suffix=".jsp" />
<!--
The index controller.
-->
<bean name="indexController"
class="org.springframework.web.servlet.mvc.ParameterizableViewController"
p:viewName="index" />
</beans>
hibernate.cfg.xml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<property name="hibernate.connection.driver_class">oracle.jdbc.OracleDriver</property>
<property name="hibernate.connection.username">scott</property>
<property name="hibernate.connection.password">tiger</property>
<property name="hibernate.connection.url">jdbc:oracle:thin:@localhost:1521:orcl</property>
<property name="hibernate.current_session_context_class">thread</property>
<mapping resource="com/entity/EmpTest.hbm.xml"/>
</session-factory>
</hibernate-configuration>
EmpModelImpl.java
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package com.model;
import com.entity.EmpTest;
import com.util.HibernateUtil;
import java.math.BigDecimal;
import java.util.List;
import org.hibernate.SessionFactory;
import org.springframework.stereotype.Repository;
@Repository
public class EmpModelImp {
private SessionFactory session;
public void add(EmpTest emp) {
session=HibernateUtil.getSessionFactory();
session.getCurrentSession().save(emp);// throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
}
public void updateEmp(EmpTest emp) {
session=HibernateUtil.getSessionFactory();
session.getCurrentSession().update(emp);// throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
}
public void delete(BigDecimal EmpId) {
session=HibernateUtil.getSessionFactory();
session.getCurrentSession().delete(getEmp(EmpId));// throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
}
public EmpTest getEmp(BigDecimal EmpId) {
session=HibernateUtil.getSessionFactory();
return (EmpTest) session.getCurrentSession().get(EmpTest.class, EmpId);// //throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
}
public List<EmpTest> getAll() {
session=HibernateUtil.getSessionFactory();
return session.getCurrentSession().createCriteria("from emptest").list(); //throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
}
}
EmpServiceImpl.java
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package com.model;
import com.entity.EmpTest;
import java.math.BigDecimal;
import java.util.List;
import org.springframework.stereotype.Service;
import org.springframework.transaction.annotation.Transactional;
@Service
public class EmpServiceImpl {
private EmpModelImp dao;
public EmpServiceImpl() {
this.dao = new EmpModelImp();
}
@Transactional
public void add(EmpTest emp) {
dao.add(emp);
}
@Transactional
public void updateEmp(EmpTest emp) {
dao.updateEmp(emp);
}
@Transactional
public void delete(BigDecimal EmpId) {
dao.delete(EmpId);
}
@Transactional
public EmpTest getEmp(BigDecimal EmpId) {
return dao.getEmp(EmpId);
}
@Transactional
public List<EmpTest> getAll() {
return dao.getAll();
}
}
我得到以下异常。
org.hibernate.HibernateException: createCriteria is not valid without active transaction
org.hibernate.context.internal.ThreadLocalSessionContext$TransactionProtectionWrapper.invoke(ThreadLocalSessionContext.java:352)
com.sun.proxy.$Proxy98.createCriteria(Unknown Source)
com.model.EmpModelImp.getAll(EmpModelImp.java:51)
com.model.EmpServiceImpl.getAll(EmpServiceImpl.java:47)
您还需要开始和结束事务。
Session session = HibernateUtil.getSessionFactory().getCurrentSession();
session.beginTransaction();
EmpTest empTest = (EmpTest) session.get(EmpTest.class, EmpId);
session.getTransaction().commit();
你当然可以要求spring为你做事务管理。但是为此,您需要配置额外的transactionmanager bean。
您通过呼叫getCurrentSession()
得到您的Session
。这给出了"当前会话",它绑定到事务的生命周期,并将在事务结束(提交或回滚)时自动刷新和关闭。因此,在这种情况下,必须显式地开始transaction
。不要忘记commit
,否则您的会话将保持打开状态,连接将不会被释放。
或者,如果你决定使用sessionFactory.openSession()
,你必须自己管理会话,并"手动"刷新和关闭它。在这种情况下,您不需要显式地为只读操作启动事务。
将@Transactional移到模型Impl类中,使其为
@Transactional
@Repository
public class EmpModelImp{..}
我认为你必须在HQL查询中用大写字母写from EmpTest
public List<EmpTest> getAll() {
session=HibernateUtil.getSessionFactory();
return session.getCurrentSession().createCriteria("from Emptest").list();
}