我正在为spring安全认证创建一个简单的jsf login form
:
<form action="#{request.contextPath}/j_spring_security_check" method="post">
<h:outputLabel for="j_username" value="Username"/>
<h:inputText id="j_username"/>
<br/>
<h:outputLabel for="j_password" value="Password"/>
<h:inputSecret id="j_password"/>
<br/>
<h:commandButton value="Login"/>
</form>
这是applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security.xsd">
<security:http auto-config="true" use-expressions="true">
<security:intercept-url pattern="/login.xhtml" access="hasRole('IS_AUTHENTICATED_ANONYMOUSLY')"/>
<security:intercept-url pattern="/**" access="hasRole('ROLE_USER')"/>
<security:form-login login-page="/login.xhtml" default-target-url="/" authentication-failure-url="/login?login_error=1"/>
</security:http>
<security:authentication-manager>
<security:authentication-provider>
<security:user-service>
<security:user name="sajjad" password="200200" authorities="ROLE_USER"/>
</security:user-service>
</security:authentication-provider>
</security:authentication-manager>
</beans>
和web.xml
:
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
<dispatcher>FORWARD</dispatcher>
</filter-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
和faces-context.xml
:
<application>
<el-resolver>org.springframework.web.jsf.el.SpringBeanFacesELResolver</el-resolver>
</application>
代码有什么问题?
添加login-processing-url="/j_spring_security_check"
到<security:http>
尝试将<dispatcher>REQUEST</dispatcher>
添加到springSecurityFilterChain映射