如何根据坐标过滤数据

Question

在我的应用程序中，我有很多位置，根据当前位置，我需要过滤结果，只显示半径为5英里的结果。有办法做到这一点吗？？

谢谢，

Answer 1

CLLocation与Location有距离，可以像一样调用

CLLocation dist = [locationA distanceFromLocation:locationB];

Answer 2

试试这个函数。这将对你有所帮助。

-(void)distanceBetween{

double latitude1 = [merchant.latitude doubleValue];
double longitude1 = [merchant.longitude doubleValue];
NSUserDefaults *userLocation = [NSUserDefaults standardUserDefaults];
float lat = [userLocation floatForKey:@"latitude"];
float lon = [userLocation floatForKey:@"longitude"];

CLLocation *locA = [[CLLocation alloc] initWithLatitude:latitude1 longitude:longitude1];
CLLocation *locB = [[CLLocation alloc] initWithLatitude:lat longitude:lon];
CLLocationDistance distanceTo = [locA distanceFromLocation:locB];
NSLog(@"locaA is %f", locA);
NSLog(@"locaB is %f", locB);
NSLog(@"locdistnace is %f", distanceTo);
[[self distance] setText:[NSString stringWithFormat:@"%0.2f miles", distanceTo/1609.34]];
}

Answer 3

类似的东西应该可以工作，但还没有测试过：

- (NSArray *)filterArrayOfLocations:(NSArray *)array byDistance:(CLLocationDistance)distance toCurrentLocation:(CLLocation*)currentLocation
{
    NSArray *filteredArray = [array filteredArrayUsingPredicate:[NSPredicate predicateWithBlock:^BOOL(id evaluatedObject, NSDictionary *bindings) {
        return [currentLocation distanceFromLocation:(CLLocation *)evaluatedObject] < distance;
    }]];
    return filteredArray;
}