在Python中，如何在左侧的2个分隔符和右侧的7个分隔符之间隔离文本

Question

我有一个字符串：

string = ""7807161604","Sat Jan 16 00:00:57 +0000 2010","Global focus begins tonight. Pretty interested to hear more about it.","Madison Alabama","al","17428434","81","51","Sun Nov 16 21:46:24 +0000 2008","243"

我只想要文本："全球焦点今晚开始。很想了解更多信息。"介于第2个和第3个逗号/分隔符之间。如果我使用：

i = string.split(',', 2)
s = i[2]
j = s.split(',',-7)
print j[0]

我会得到想要的输出。但是，如果原始字符串之间有一个额外的逗号，如下所示：

string = ""7807161604","Sat Jan 16 00:00:57 +0000 2010","Global focus begins tonight. Pretty interested, to hear more about it.","Madison Alabama","al","17428434","81","51","Sun Nov 16 21:46:24 +0000 2008","243""

然后这种方法就不起作用了，因为我需要的输出正在被分割。如果我做错了，有人能帮忙并提出不同的方法或建议吗？谢谢

Answer 1

您可以使用python内置的csv模块来完成此操作。

j = next(csv.reader([string]));

现在，j是由,分隔的每个项，并且如果值被封装在"中，则将包括逗号。参见j[2]。