将登录设置为我的主页时.xhtml它不起作用

Question

当我将登录.xhtml页面设置为Web.xml作为欢迎文件时，它不起作用，我的意思是它可以很好地显示页面，但是当我按登录时没有任何反应，但是当我手动转到登录页面时http://localhost:8080/fileuploadWithPreview/login.xhtml它运行良好，任何想法为什么会这样？

网站.xml ：

       <?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee         http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <filter>
        <filter-name>Upload Filter</filter-name>
        <filter-class>richard.fileupload.UploadFilter</filter-class>
        <init-param>
            <param-name>sizeThreshold</param-name>
            <param-value>1024</param-value>
        </init-param>
    </filter>
    <filter-mapping>
        <filter-name>Upload Filter</filter-name>
        <url-pattern>/faces/upload/*</url-pattern>
    </filter-mapping>
    <servlet>
        <servlet-name>Faces Servlet</servlet-name>
        <servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>Faces Servlet</servlet-name>
        <url-pattern>*.xhtml</url-pattern>
    </servlet-mapping>
    <welcome-file-list>
        <welcome-file>/index.xhtml</welcome-file>
    </welcome-file-list>
    <context-param>
        <param-name>javax.faces.PROJECT_STAGE</param-name>
        <param-value>Development</param-value>
    </context-param>
    <context-param>
        <param-name>facelets.LIBRARIES</param-name>
        <param-value>/WEB-INF/corejsf.taglib.xml</param-value>
    </context-param>
    <context-param>
        <param-name>javax.faces.INTERPRET_EMPTY_STRING_SUBMITTED_VALUES_AS_NULL</param-name>
        <param-value>true</param-value>
    </context-param>
    <login-config>
        <auth-method>FORM</auth-method>
        <realm-name>LDAP</realm-name>
        <form-login-config>
            <form-login-page>/login.xhtml</form-login-page>
            <form-error-page>/login-failed.xhtml</form-error-page>
        </form-login-config>
    </login-config>
    <security-role>
        <role-name>user</role-name>
    </security-role>
    <security-constraint>     
        <!-- web resources that are protected -->
        <web-resource-collection>
            <web-resource-name>All Resources</web-resource-name>
            <url-pattern>/*</url-pattern>
            <!-- this is currently causing a 404 -->
            <http-method>GETLIB</http-method>
            <http-method>COPY</http-method>
            <http-method>MOVE</http-method>
            <http-method>DELETE</http-method>
            <http-method>PROPFIND</http-method>
            <http-method>GET</http-method>
            <http-method>HEAD</http-method>
            <http-method>PUT</http-method>
            <http-method>MKCOL</http-method>
            <http-method>PROPPATCH</http-method>
            <http-method>LOCK</http-method>
            <http-method>UNLOCK</http-method>
            <http-method>VERSION-CONTROL</http-method>
            <http-method>CHECKIN</http-method>
            <http-method>CHECKOUT</http-method>
            <http-method>UNCHECKOUT</http-method>
            <http-method>REPORT</http-method>
            <http-method>UPDATE</http-method>
            <http-method>CANCELUPLOAD</http-method>
        </web-resource-collection>
        <auth-constraint>
            <role-name>*</role-name>
        </auth-constraint>
    </security-constraint>
</web-app>

好的，它正在工作，只是当我按下登录按钮时，它会带我回到登录页面，但它已经对用户进行身份验证，我如何在登录按钮上让它进入索引.html页面一旦经过身份验证？

登录页面 ：

<div id="site_content">
    <div id="content">
        <h:body>
            <form method="post" action="j_security_check">
                <p>You need to log in to access protected information.</p>
                <table>
                    <tr>
                        <td>User name:</td>
                        <td><input type="text" name="j_username" /></td>
                    </tr>
                    <tr>
                        <td>Password:</td>
                        <td><input type="password" name="j_password" /></td>
                    </tr>
                </table>
                <p><input type="submit" value="Login" />
                    <!--<h:commandButton value="This will reset all the data " type="button" > </h:commandButton> -->
                    <input type="reset" name="Login-reset" value="Reset" onclick="alert('This will reset all the data');" />
                </p>
            </form>
        </h:body>
    </div>
</div>

Answer 1

将<url-pattern>/faces/*</url-pattern>替换为<url-pattern>*.xhtml</url-pattern>并删除所有URL中的所有/faces/路径。这样，一切都应该按预期工作。

说明：<welcome-file>需要当前请求的文件夹（！）中物理存在的文件，该文件应该已被index.xhtml或login.xhtml，而<form-login-page>需要一个应该/faces/login.xhtml的完整URI。当您对 JSF 使用文件夹映射时，这不能很好地混合。因此，只需将其映射到*.xhtml，您永远不必担心虚拟URL。

另请参阅：

• JSF Facelets：有时我看到URL是.jsf，有时是.xhtml。为什么？