bash的浮点精度

Question

我有:

DIFF=$(( ($END - $START) / 60 ))
echo "Build took $DIFF minutes" 

我1:30分钟的输出是:

Build took 1 minutes

我如何在这里使用浮点数，以便我的输出将是:

Build took 1.50 minutes

Answer 1

使用BC获取精度

的例子:

kent$  echo "scale=2;(190-100)/60"|bc
1.50

用变量替换硬编码的数字

Answer 2

我认为bash不支持浮点数。您可以使用bc命令:

DIFF=$(bc <<< "scale=2; ($END - $START) / 60")
echo "Build took $DIFF minutes"