将元组列表水平写入文本文件

Question

我有一个元组列表，如下所示:

listo = [ (A,1),(B,2),(C,3) ]

我想把这个列表写入一个文件，如下所示:

A   B   C
1   2   3

我尝试了以下命令，它给出了如下输出:

with open('outout.txt', 'w') as f:
    for x, y in listo:
        f.write("{0}t{1}n".format(x,y)
A   1
B   2
C   3

我尝试切换f.write函数中的t和n，并使用格式函数。毫无效果。

我在这里错过了什么?

Answer 1

csv模块当然可以在这里帮助您:

首先，通过调用zip分离出头和值。然后用csv

将它们写到你的文件中

In [15]: listo
Out[15]: [('A', 1), ('B', 2), ('C', 3)]
In [16]: headers, vals = zip(*listo)
In [17]: headers
Out[17]: ('A', 'B', 'C')
In [18]: vals
Out[18]: (1, 2, 3)

完整的解决方案:

import csv
listo = [(A,1), (B,2), (C,3)]
headers, vals = zip(*listo)
with open('output.txt', 'w') as outfile:
    writer = csv.writer(outfile, delimiter='t')
    writer.writerow(headers)
    writer.writerow(vals)

Answer 2

一种方法是将每个元组中的两个元素分隔成两个不同的列表(或元组)

with open('outout.txt', 'w') as f:
    for x, y in listo:
        f.write("{}t".format(x))
    f.write("n")
    for x, y in listo:
        f.write("{}t".format(y))

或者您可以使用join

a = "t".join(i[0] for i in listo)
b = "t".join(i[1] for i in listo)
with open('outout.txt', 'w') as f:
    f.write("{}n{}".format(a,b))

Answer 3

首先需要对列表进行转置/解压缩。这是用习惯用法zip(*list_)完成的。

# For Python 2.6+ (thanks iCodez):
# from __future__ import print_function
listo = [("A", 1), ("B", 2), ("C", 3)]
transposed = zip(*listo)
letters, numbers = transposed
with open("output.txt", "w") as output_txt:
    print(*letters, sep="t", file=output_txt)
    print(*numbers, sep="t", file=output_txt)

File output.txt:

A   B   C
1   2   3

Answer 4

试着分开循环:

with open('outout.txt', 'w') as f:
for x in listo:
    f.write('{}t'.format(x[0])) # print first element with tabs
f.write('n') # print a new line when finished with first elements
for y in listo:
    f.write('{}t'.format(x[1])) # print second element with tabs
f.write('n') # print another line

Answer 5

>>> A = 'A'
>>> B = 'B'
>>> C = 'C'
>>> listo = [ (A,1),(B,2),(C,3) ]
>>> print(*zip(*listo))
('A', 'B', 'C') (1, 2, 3)
>>> print(*('t'.join(map(str, item)) for item in zip(*listo)), sep='n')
A       B       C
1       2       3
>>> with open('outout.txt', 'w') as f:
...     for item in zip(*listo):
...         f.write('t'.join(map(str, item)) + 'n')
...