根据营业时间确定业务是否打开/关闭

Question

如果时间是上午到下午（例如：上午11点到晚上10点），我的代码可以正常工作，但如果位置操作时间是上午至上午（例如：早上9点到凌晨1点），代码就会中断。这是我的代码：

$datedivide = explode(" - ", $day['hours']); //$day['hours'] Example 11:00 AM - 10:00 PM
$from = ''.$day['days'].' '.$datedivide[0].'';
$to = ''.$day['days'].' '.$datedivide[1].'';
$date = date('l g:i A');
$date = is_int($date) ? $date : strtotime($date);
$from = is_int($from) ? $from : strtotime($from);
$to = is_int($to) ? $to : strtotime($to);
if (($date > $from) && ($date < $to) && ($dateh != 'Closed')) {
    ?>
    <script type="text/javascript">
    $(document).ready(function(){
        $('.entry-title-container').append('<div class="column two"><h2 style="color:green;text-align: left;margin: 0;">OPEN<br /><span style="color:#222;font-size:12px;display: block;">Closes at <?php echo $datedivide[1]; ?></span></h2></div><br clear="all" />');
    });
    </script>
    <?php
}

Answer 1

您首先需要创建一个数组，其中包含一周中的几天以及它们各自的关闭/打开时间范围。

/**
 * I setup the hours for each day if they carry-over)
 * everyday is open from 09:00 AM - 12:00 AM
 * Sun/Sat open extra from 12:00 AM - 01:00 AM
 */
$storeSchedule = [
    'Sun' => ['12:00 AM' => '01:00 AM', '09:00 AM' => '12:00 AM'],
    'Mon' => ['09:00 AM' => '12:00 AM'],
    'Tue' => ['09:00 AM' => '12:00 AM'],
    'Wed' => ['09:00 AM' => '12:00 AM'],
    'Thu' => ['09:00 AM' => '12:00 AM'],
    'Fri' => ['09:00 AM' => '12:00 AM'],
    'Sat' => ['12:00 AM' => '01:00 AM', '09:00 AM' => '12:00 AM']
];

然后循环当前日期的时间范围，并检查当前时间或提供的时间戳是否在范围内。您可以通过使用DateTime类为每个时间范围的开始/结束时间生成DateTime对象来完成此操作。

以下内容将执行此操作，并允许您指定时间戳，以防您想要检查提供的时间戳而不是当前时间。

// current or user supplied UNIX timestamp
$timestamp = time();
// default status
$status = 'closed';
// get current time object
$currentTime = (new DateTime())->setTimestamp($timestamp);
// loop through time ranges for current day
foreach ($storeSchedule[date('D', $timestamp)] as $startTime => $endTime) {
    // create time objects from start/end times
    $startTime = DateTime::createFromFormat('h:i A', $startTime);
    $endTime   = DateTime::createFromFormat('h:i A', $endTime);
    // check if current time is within a range
    if (($startTime < $currentTime) && ($currentTime < $endTime)) {
        $status = 'open';
        break;
    }
}
echo "We are currently: $status";

参见上述的演示

Answer 2

根据公认的答案修改，用于AWS Debian服务器（位于西海岸），我们的营业时间实际上是EST。。。还放入了一个PHP函数中。

/*
 * decide based upon current EST if the store is open
 *
 * @return bool
 */
function storeIsOpen() {
    $status = FALSE;
    $storeSchedule = [
        'Mon' => ['08:00 AM' => '05:00 PM'],
        'Tue' => ['08:00 AM' => '05:00 PM'],
        'Wed' => ['08:00 AM' => '05:00 PM'],
        'Thu' => ['08:00 AM' => '05:00 PM'],
        'Fri' => ['08:00 AM' => '05:00 PM']
    ];
    //get current East Coast US time
    $timeObject = new DateTime('America/New_York');
    $timestamp = $timeObject->getTimeStamp();
    $currentTime = $timeObject->setTimestamp($timestamp)->format('H:i A');
    // loop through time ranges for current day
    foreach ($storeSchedule[date('D', $timestamp)] as $startTime => $endTime) {
        // create time objects from start/end times and format as string (24hr AM/PM)
        $startTime = DateTime::createFromFormat('h:i A', $startTime)->format('H:i A');
        $endTime = DateTime::createFromFormat('h:i A', $endTime)->format('H:i A');
        // check if current time is within the range
        if (($startTime < $currentTime) && ($currentTime < $endTime)) {
            $status = TRUE;
            break;
        }
    }
    return $status;
}

Answer 3

您应该将所有营业时间重新组合在一个数组中，因为如果您在午夜后继续营业，昨天的营业时间可能会产生影响。此外，每天有几个开放时间可能会很方便。

<?php
$times = array(
    'mon' => '9:00 AM - 12:00 AM',
    'tue' => '9:00 AM - 12:00 AM',
    'wed' => '9:00 AM - 12:00 AM',
    'thu' => '9:00 AM - 12:00 AM',
    'fri' => '9:00 AM - 1:00 AM',
    'sat' => '9:00 AM - 1:00 PM, 2:00 PM - 1:00 AM',
    'sun' => 'closed'
);
function compileHours($times, $timestamp) {
    $times = $times[strtolower(date('D',$timestamp))];
    if(!strpos($times, '-')) return array();
    $hours = explode(",", $times);
    $hours = array_map('explode', array_pad(array(),count($hours),'-'), $hours);
    $hours = array_map('array_map', array_pad(array(),count($hours),'strtotime'), $hours, array_pad(array(),count($hours),array_pad(array(),2,$timestamp)));
    end($hours);
    if ($hours[key($hours)][0] > $hours[key($hours)][1]) $hours[key($hours)][1] = strtotime('+1 day', $hours[key($hours)][1]);
    return $hours;
}
function isOpen($now, $times) {
    $open = 0; // time until closing in seconds or 0 if closed
    // merge opening hours of today and the day before
    $hours = array_merge(compileHours($times, strtotime('yesterday',$now)),compileHours($times, $now)); 
    foreach ($hours as $h) {
        if ($now >= $h[0] and $now < $h[1]) {
            $open = $h[1] - $now;
            return $open;
        } 
    }
    return $open;
}
$now = strtotime('7:59pm');
$open = isOpen($now, $times);
if ($open == 0) {
    echo "Is closed";
} else {
    echo "Is open. Will close in ".ceil($open/60)." minutes";
}
?>

另一方面，如果你只想像9am - 5am那样用时间来解决问题，你应该检查$from > $to是否存在，并在必要时在$to中添加1天。

Answer 4

有点晚了，但我有一个适合其他人的解决方案，如果这里的解决方案不太符合他们的需求。我确实喜欢为午夜后结束的几天设置多个时间集的解决方案，但这会增加额外的数据处理来显示时间。您首先必须检查是否有多个可用的时间集，然后确认它们已连接（其间没有时间）。

相反，我的解决方案是编写一个函数，通过打开时间、关闭时间和有问题的时间，它将为打开返回true，为关闭返回false：

function is_open($open, $close, $query_time){
    $open = new DateTime($open);
    $close = new DateTime($close);
    $query_time = new DateTime($query_time);
    $is_open = false;
    //Determine if open time is before close time in a 24 hour period
    if($open < $close){
        //If so, if the query time is between open and closed, it is open
        if($query_time > $open){
            if($query_time < $close){
                $is_open = true;
            }
        }
    }
    elseif($open > $close){
        $is_open = true;
        //If not, if the query time is between close and open, it is closed
        if($query_time < $open){
            if($query_time > $close){
                $is_open = false;
            }
        }
    }
    return $is_open;
}

Answer 5

也许是这样？我在这里找到了它，并对它进行了一些调整。

    <?php
    date_default_timezone_set('Europe/Stockholm'); // timezone 
    $today = date(N); // today ex. 6
    //Opening hours
    $opening_hours[1] = "12:00"; $closing_hours[1] = "00:00";
    $opening_hours[2] = "12:00"; $closing_hours[2] = "00:00";
    $opening_hours[3] = "12:00"; $closing_hours[3] = "00:00";
    $opening_hours[4] = "12:00"; $closing_hours[4] = "02:00";
    $opening_hours[5] = "12:00"; $closing_hours[5] = "04:00";
    $opening_hours[6] = "13:00"; $closing_hours[6] = "04:00";
    $opening_hours[7] = "13:00"; $closing_hours[7] = "00:00";
    // correction for opening hours after midnight.
    if(intval($closing_hours[$today - 1]) > 0)
        $today = date(N,strtotime("-".intval($closing_hours[$today - 1])." hours"));
    // now check if the current time is after openingstime AND smaller than closing hours of tomorrow
            if (
    (date("H:i") > $opening_hours[$today] && 
    ((date("Y-m-d H:i") < date("Y-m-d H:i", strtotime('tomorrow +'.intval($closing_hours[$today]).' hours')))) 
    ) ||
    date("H:i") < $closing_hours[$today] && 
    ((date("Y-m-d H:i") < date("Y-m-d H:i", strtotime('today +'.intval($opening_hours[$today]).' hours'))))
    )  {
        $label = "label-success";   
        $label_text = "OPEN";
        $label_time = $closing_hours[$today];
    } else {
        $label = "label-danger";
        $label_text = "GESLOTEN";
        $label_time = $opening_hours[$today];
    }
    ?>

Answer 6

我用几种不同的方法尝试了这段代码一天，发现这对我来说是一个解决方案。将时间从AM/PM格式转换回UNIX时间非常重要。

我使用从数据库中提取的时间，因此您必须定义$startTime和$endTime。

//  define each days time like so
$monsta = "07:00 AM";
$monend = "05:00 PM";
$storeSchedule = [
    'Mon' => ["$monsta" => "$monend"],
    'Tue' => ["$tuessta" => "$tuesend"],
    'Wed' => ["$wedssta" => "$wedsend"],
    'Thu' => ["$thurssta" => "$thursend"],
    'Fri' => ["$frista" => "$friend"],
    'Sat' => ["$satsta" => "$satend"],
    'Sun' => ["$sunsta" => "$sunend"]
];
// default time zone
$timestamp = time() - 18000; 
// default status
$status = 'Closed';
// loop through time ranges for current day
foreach ($storeSchedule[date('D', $timestamp)] as $startTime => $endTime) {
// create time objects from start/end times
$startTime = strtotime($startTime);
$endTime = strtotime($endTime);
// check if current time is within a range
if ($startTime <= $timestamp && $timestamp <= $endTime ) {
    $status = 'Open';
    }
}   
echo '<p><b>Today's Hours</b><br />'.$days[$d].'<br />';
echo "<b>We are currently: $status </b></p>";

Answer 7

这是我的版本，因为12小时的时间格式不适合我。注意$panchits[]来自我的数据库

$status = 'Closed';
// get current time object
$timestamp = time();
// $currentTime = (new DateTime())->setTimestamp($timestamp);
$currentTime = date('H:i');
$startTime = date('H:i', strtotime($pancits['p_oTime']));
$endTime   = date('H:i', strtotime($pancits['p_cTime']));
if (($startTime <= $currentTime) && ($currentTime <= $endTime)) {
    $status = 'Open';
    //echo $status;
}
echo "<b>Currently $status</b>";
echo '
    <p><b>Time Open: </b>'.date('h:ia', strtotime($pancits['p_oTime'])).'</p>
    <p><b>Time Close: </b>'.date('h:ia', strtotime($pancits['p_cTime'])).'</p>
';

Answer 8

我建议使用PHP的DateTime类。它是为了解决所有这些问题而开发的，它为像这样难以完成的任务提供了一个简单的界面。